When a golf ball of mass m = 0.11 kg is dropped from a height h. It interacts with the floor for t = 0.195 s, and applies a force of F = 10.5 N to the floor when it elastically collides with it. What is the expression for the golf ball's velocity v in terms of the variables m, t, and F just after it rebounds from the floor? From knowing this how can we know the ball's magnitude of it's velocity (v) in meters per squared second?
When a golf ball of mass m = 0.11 kg is dropped from a height h. It interacts with the floor for t = 0.195 s, and applies a force of F = 10.5 N to the floor when it elastically collides with it. What is the expression for the golf ball's velocity v in terms of the variables m, t, and F just after it rebounds from the floor? From knowing this how can we know the ball's magnitude of it's velocity (v) in meters per squared second?
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter8: Momentum And Collisions
Section: Chapter Questions
Problem 31P
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When a golf ball of mass m = 0.11 kg is dropped from a height h. It interacts with the floor for t = 0.195 s, and applies a force of F = 10.5 N to the floor when it elastically collides with it.
What is the expression for the golf ball's velocity v in terms of the variables m, t, and F just after it rebounds from the floor? From knowing this how can we know the ball's magnitude of it's velocity (v) in meters per squared second?
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