When 60.0 mL of a 0.400 M solution of HN03 (ag) is combined with 60.0 mL of a 0.400 M solution of NaOH(ag) in a coffee-cup calorimeter, the final temperature of the solution is measured to be 26.6 °C. The initial temperature of the solutions is 24.0 °C. Calculate qn in joules, assuming the specific heat capacity of the final solution is 3.90 J-g. C1, the density of the final solution is 1.04 g/mL, and the calorimeter constant is 45 J/°C. (Hint: start with qxn + qsoin + qcai = 0.) The balanced chemical equation for this reaction is: HNO3 (ag) + NaOH(ag) + H2O) + NaNO3 (ag) Answer: -1382.472 J

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Chapter6: Thermochemistry
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I have tried so many different digits and it is still wrong! Please help what is the right number thanks. I have used all the decimal and one by one and still is wrong please help
When 60.0 mL of a 0.400 M solution of HNO3 (ag) is combined with 60.0 mL of a 0.400 M solution of NaOHa0) in a coffee-cup
calorimeter, the final temperature of the solution is measured to be 26.6 °C. The initial temperature of the solutions is 24.0 °C.
Calculate qran in joules, assuming the specific heat capacity of the final solution is 3.90 J-g1.°C, the density of the final solution is 1.04
g/mL, and the calorimeter constant is 45 J/°C. (Hint: start with gan + qeoln + qeai = 0.)
Main Content
The balanced chemical equation for this reaction is:
HNO3 (ag) + NaOH(ag) → H2O) + NANO3 (ag)
Answer:
-1382.472 J
Transcribed Image Text:When 60.0 mL of a 0.400 M solution of HNO3 (ag) is combined with 60.0 mL of a 0.400 M solution of NaOHa0) in a coffee-cup calorimeter, the final temperature of the solution is measured to be 26.6 °C. The initial temperature of the solutions is 24.0 °C. Calculate qran in joules, assuming the specific heat capacity of the final solution is 3.90 J-g1.°C, the density of the final solution is 1.04 g/mL, and the calorimeter constant is 45 J/°C. (Hint: start with gan + qeoln + qeai = 0.) Main Content The balanced chemical equation for this reaction is: HNO3 (ag) + NaOH(ag) → H2O) + NANO3 (ag) Answer: -1382.472 J
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