When 38.0 mL of 0.1250 M H2SO4 is added to 100. mL of a solution of Pb(NO3)2, a precipitate of PbS04 forms. The PbSO4 is then filtered from the solution, dried, and weighed. If the recovered PbSO4 is found to have a mass of 0.0471 g, what was the concentration of lead nitrate in the original solution? O A. 3.10 x 10-4M O B. 1.55 x 10-4 M OC. 1.55 x 10-3 M O D. 6.20 x 10-3 M O E. 3.11 x 10-3 M

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When 38.0 mL of 0.1250 M H,SO4 is added to 100. mL of a solution of Pb(NO2)2, a precipitate of PbSO4 forms. The PbSO4 is then filtered from the solution,
dried, and weighed. If the recovered PbSO4 is found to have a mass of 0.0471 g, what was the concentration of lead nitrate in the original solution?
O A. 3.10 x 104M
O B. 1.55 x 10-4 M
OC1.55 x 10-3 M
O D. 6.20 x 103 M
O E
3.11 x 103 M
Transcribed Image Text:When 38.0 mL of 0.1250 M H,SO4 is added to 100. mL of a solution of Pb(NO2)2, a precipitate of PbSO4 forms. The PbSO4 is then filtered from the solution, dried, and weighed. If the recovered PbSO4 is found to have a mass of 0.0471 g, what was the concentration of lead nitrate in the original solution? O A. 3.10 x 104M O B. 1.55 x 10-4 M OC1.55 x 10-3 M O D. 6.20 x 103 M O E 3.11 x 103 M
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