0.8159 g sample of HCl issolved in water to make e titration. What is the E り.859g Hil

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A 0.8159 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly
dissolved in water to make 50 mL of solution. It required 22.07 mL of NaOH to reach the endpoint in
the titration. What is the molarity of the NaOH solution?
I mg IHE/
2.022 4 mol
0.81599 Hcl
36.4bg.
Transcribed Image Text:A 0.8159 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly dissolved in water to make 50 mL of solution. It required 22.07 mL of NaOH to reach the endpoint in the titration. What is the molarity of the NaOH solution? I mg IHE/ 2.022 4 mol 0.81599 Hcl 36.4bg.
Expert Solution
Step 1

Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;

Molarity = molesvolume (L)

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