A 0.8159 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughlydissolved in water to make 50 mL of solution. It required 22.07 mL of NaOH to reach the endpoint inthe titration. What is the molarity of the NaOH solution?I mg IHE/2.022 4 mol0.81599 Hcl36.4bg.

Answered: 0.8159 g sample of HCl issolved in…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A 0.8159 g sample of HCl was placed into a 50 mL volumetric flask and the sample was thoroughly
dissolved in water to make 50 mL of solution. It required 22.07 mL of NaOH to reach the endpoint in
the titration. What is the molarity of the NaOH solution?
I mg IHE/
2.022 4 mol
0.81599 Hcl
36.4bg.

Expert Solution

Step 1

Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;

$M o l a r i t y = \frac{m o l e s}{v o l u m e (L)}$

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