When 38 campers are randomly selected and surveyed, it was found that the average number that prefer to camp at the beach was 24. Assume the population standard deviation is 10.7. Construct a 99% confidence interval for the true population mean of the number of campers who prefer to camp at the beach.

Q: Researchers found that in certain counties in the country, females spend an average of 65 days in…

A: standard deviationσ=4n=36x¯=65

Q: A study of peach trees found that the average number of peaches per tree was 625.  The standard…

A:

Q: a)  A histogram of time spent eating and drinking each day is skewed right. Use this result to…

A: From given data we have : sample size n = 1072 mean x=1.35 standard deviation σ=0.53

Q: You are a researcher for the National Highway Traffic Safety Administ estimate the average blood…

A: Given that,The sample size is The sample mean BAC (Blood Alcohol Concentration) is The known…

Q: When 33 campers are randomly selected and surveyed, it was found that the average number that prefer…

A: Given Information: Number of campers randomly selected, n =33 Avarege numple of peope prefer to camp…

Q: The mean hours of worked for United Airlines pilots is 46 hours/month based upon a sample of 25…

A: Given: Sample size, n=25 Sample mean, X=46 hours Sample standard deviation, s=3 hours The level of…

Q: Suppose that a 92% Confidence Interval for estimating the average heights, in inches, of all college…

A: confidence interval = x ± margin of errorlower limit = x - margin of errorupper limit = x + margin…

Q: The average weight of 36 randomly selected school buses was 4150 pounds with a standard deviation of…

A: Given data,x=4150σ=480n=36z-value at 99% confidence is Zc=2.576

Q: ta 99% confidence interval for the mean number of hours a student studies per week. Assume that the…

A: We are going to find 99% confidence interval by finding the critical value

Q: what would the 95% confidence limits for a sample of 120 with a mean of 51 and a standard deviation…

A: It is given that mean and standard deviation are 51 and 12, respectively.

Q: A study was conducted to determine the effectiveness of hypnotism on reducing pain. Using standard…

A: Sample 1(before hypnosis): n1=8x¯1=8.713s1=2.177 Sample 2(after hypnosis): n2=8x¯2=5.588s2=2.608

Q: he average weight of 20 randomly selected cars was 3500 pounds. The sample standard deviation was…

A: given data, n=20df=n-1=20-1=19x¯=3500 pounds s=315 pounds CI=0.90α=1-0.90=0.10

Q: 1. The mean and standard deviation of a process are expected to be about μ = 400 and σ = 16. An…

A: cTo calculate the required sample size ( n ) for estimating the population mean with a specified…

Q: In a random sample of 12 people, the mean commute time to work was 30 minutes and the sample…

A:

Q: x¯ = Margin of error at 90% confidence level = 90% confidence interval =

A: Given: n=8 Confidence level=90% Height, X 67 66 64 75 63 67 72 71

Q: A marine biologist is interested in whether the chinook salmon a particular species of salmon in the…

A: The value of sample mean is, x¯=36 The value of margin of error is, ME= 9

Q: A large urgent care center with 4 doctors found that they can see an average of 28 patients per…

A: We have given that Sample size (n) = 41Sample mean (x̅) = 28Standard deviations (s) =…

Q: The distribution of study times for first-year students follows a normal distribution with a…

A:

Q: In a survey, 24 people were asked how much they spent on their child's birthday party. The results…

A: Introduction: The 100 (1 – α) % confidence interval for the population mean, μ, when the population…

Q: A data set includes 109 body temperatures of healthy adult humans having a mean of 98.2°F and a…

A: The random variable X follows normal distribution. The sample size is 109. The sample mean is 98.2.…

Q: A food snack manufacturer samples 9 bags of pretzels off the assembly line and weighs their…

A: Given information Sample size (n) = 9 Sample mean x̅ = 15.2 oz Standard deviation (s) = 0.50 oz…

Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…

A: We have given data,  Less attendance Full attendance 90 96 90 96 60 100 50 99 69   88…

Q: Dr. Moore wanted to estimate the mean cholesterol level for all adult men living in Hartford... He…

A:

Q: A runner wants to know her average mile running time. She records a sample of 25 running times. The…

A: Solution: Let X be the mile running time. From the given information, x-bar=6.5 minutes, s=0.7…

Q: Brown measured his book using a different shaped ruler. He got different measurements, namely 30,…

A: Given that  Different measurements he got 30 , 35 , 29 , 33 , 32 , 28 , 28 , 35 Sum of data value =…

Q: Suppose from random sample of 500 teenagers, the mean number of sweaters owned was 12.5 and a…

A:

Q: You measure 41 watermelons' weights, and find they have a mean weight of 79 ounces. Assume the…

A: Mean = 79Standard deviation = 2.4Sample size = 41

Q: The age when smokers first start from previous studies is normally distributed with a mean of 13…

A: Given,sample size(n)=22sample mean(x¯)=13.8standard deviation(σ)=2.1α=1-0.90=0.1α2=0.05Z0.05=1.645…

Q: find the 99% confidence interval of the mean number of miles driven per day by all truckers

A: It is given that  Average = 540 Population standard deviation = 40 Sample size = 90

Q: A food snack manufacturer samples 11 bags of pretzels off the assembly line and weighs their…

A:

Q: A popular weight loss program claims users will lose weight each month. Linda samples 25 dieters and…

A: We have given that,  Sample mean (x̄) = 10 pounds, standard deviation (s) = 2 pounds and sample size…

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.