When 21.0 mL pentane (C5H12, d= 0.678 g/mL, M= 72 g/mol) reacts with 26.0 grams oxygen (02, M= 32 g/mol), carbon dioxide (CO2) and water (H₂0) form. a. How many moles of each reagent are there before the reaction takes place? b. Write a balanced equation for the reaction. C. What is the limiting reagent? d. What is the theoretical yield of the reaction (in moles of each product)?

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When 21.0 mL pentane (C5H12, d= 0.678 g/mL, M= 72 g/mol) reacts with 26.0 grams oxygen (02, M= 32 g/mol),
carbon dioxide (CO2) and water (H₂0) form.
a. How many moles of each reagent are there before the reaction takes place?
b. Write a balanced equation for the reaction.
C. What is the limiting reagent?
d. What is the theoretical yield of the reaction (in moles of each product)?
When 1-bromobutane (C4H9Br, d= 1.27 g/mL, and M=137 g/mol) reacts with lithium (Li, M= 6.9 g/mol), we get
n-butyl-lithium (C₂H,Li, M= 64.1 g/mol) and lithium bromide (LiBr, M= 86.8 g/mol). What is the percent yield if 92
mL of 1-bromobutane reacted with 6.9 grams of lithium and produced 18 grams of n-butyl-lithium?
C₂H₂Br + Li →→→ C4H₂Li + Libr
Transcribed Image Text:When 21.0 mL pentane (C5H12, d= 0.678 g/mL, M= 72 g/mol) reacts with 26.0 grams oxygen (02, M= 32 g/mol), carbon dioxide (CO2) and water (H₂0) form. a. How many moles of each reagent are there before the reaction takes place? b. Write a balanced equation for the reaction. C. What is the limiting reagent? d. What is the theoretical yield of the reaction (in moles of each product)? When 1-bromobutane (C4H9Br, d= 1.27 g/mL, and M=137 g/mol) reacts with lithium (Li, M= 6.9 g/mol), we get n-butyl-lithium (C₂H,Li, M= 64.1 g/mol) and lithium bromide (LiBr, M= 86.8 g/mol). What is the percent yield if 92 mL of 1-bromobutane reacted with 6.9 grams of lithium and produced 18 grams of n-butyl-lithium? C₂H₂Br + Li →→→ C4H₂Li + Libr
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