When 2-chloropropane is treated in alcohol, both elimination and substitution products are formed. The alkene product, 1-propene, is formed by an E-1 mechanism. Which of the following mechanisms is correct for this reaction? alcohol CH3 - CH-CH, CH3-CH=CH2 (+ HCI ) Heat 1-propene NOTE: R-OH is alcohol

Chemistry
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Choose either I, II, III, or IV

When 2-chloropropane is treated in alcohol, both elimination and
substitution products are formed. The alkene product, 1-propene, is formed
by an E-1 mechanism. Which of the following mechanisms is correct for this
reaction?
alcohol
CH3 -
CH-
-CH3
CH3-CH=CH,
(+ HCI )
Heat
1-propene
NOTE: R-OH is alcohol
I
:OR
H-OR
H
H
CH3-
CH3
CH3
CH2
CH3-CH=CH2
slow
H
CI-
H
:OR
II
H-OR
H
CH3 -
-CH
CH2
CH3-CH=CH2
+ CI-
III
H
NOR
H-OR O
+
H
H
CH3
CH-
CH3
CH3
slow
CH2
CH
CH3-CH=CH2
+ CI-
+ H-OR
H
:OR
H
H
IV
CH3
CH
CH2
CH3
CH2
CH-
CH3-CH=CH2
C1
slow
CI-
Transcribed Image Text:When 2-chloropropane is treated in alcohol, both elimination and substitution products are formed. The alkene product, 1-propene, is formed by an E-1 mechanism. Which of the following mechanisms is correct for this reaction? alcohol CH3 - CH- -CH3 CH3-CH=CH, (+ HCI ) Heat 1-propene NOTE: R-OH is alcohol I :OR H-OR H H CH3- CH3 CH3 CH2 CH3-CH=CH2 slow H CI- H :OR II H-OR H CH3 - -CH CH2 CH3-CH=CH2 + CI- III H NOR H-OR O + H H CH3 CH- CH3 CH3 slow CH2 CH CH3-CH=CH2 + CI- + H-OR H :OR H H IV CH3 CH CH2 CH3 CH2 CH- CH3-CH=CH2 C1 slow CI-
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