When 12 g of methanol (CH3OH) was treated with excess MnO4, 14 g of formic acid (HCOOH) was obtained. Calculate the percent yield. Note: This equation cannot be balanced as is because other things more complicated are happening. Use the reaction as it is shown below: 3CH3OH + 4MNO4 3HCOOH + 4MNO2

When 12 g of methanol (CH3OH) was treated with excess MnO4, 14 g of formic acid (HCOOH) was obtained. Calculate the percent yield. Note: This equation cannot be balanced as is because other things more complicated are happening. Use the reaction as it is shown below: 3CH3OH + 4MNO4 3HCOOH + 4MNO2

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

When 12 g of methanol (CH₃OH) was treated with excess MnO₄⁻, 14 g of formic acid (HCOOH) was obtained. Calculate the percent yield. Note: This equation cannot be balanced as is because other things more complicated are happening. Use the reaction as it is shown below:

\[3\text{CH}_3\text{OH} + 4\text{MnO}_4^- \rightarrow 3\text{HCOOH} + 4\text{MnO}_2\]

- ( ) 100%
- ( ) 92%
- ( ) 70%
- ( ) 82%
- ( ) 55%
- ( ) 32.61%
- ( ) none of these are correct

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