When 1.50 mol of CH4(g) reacts with excess Çl2(g) at constant pressure according to the chemical equation shown below, 1062 kJ of heat are released. Calculate the value of AH for this reaction, as written. 2 CH4(g) + 3 Cl2(g) → 2 CHC13(1) + 3 H2(g) ΔΗ- A) -1420 kJ B) -708 kJ C) +708 kJ D) +1420 kJ Answer: A 1.50mal CHy 10GR KJ,|| 3mol Clz 15mol CHy -796.5KJ Rmol CHy

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When 1.50 mol of CH4(g) reacts with excess Çl2(g) at constant pressure according to the chemical
equation shown below, 1062 kJ of heat are released. Calculate the value of AH for this reaction, as
written.
2 CH4(g) + 3 Cl2(g) → 2 CHC13(1) + 3 H2(g)
AH = ?
A) -1420 kJ
B) -708 kJ
C) +708 kJ
D) +1420 kJ
Answer: A
1.50 mal CHy MOGR KJT4
2mol CHy
15mol CHy
3mol Clz
-796.51J
Transcribed Image Text:When 1.50 mol of CH4(g) reacts with excess Çl2(g) at constant pressure according to the chemical equation shown below, 1062 kJ of heat are released. Calculate the value of AH for this reaction, as written. 2 CH4(g) + 3 Cl2(g) → 2 CHC13(1) + 3 H2(g) AH = ? A) -1420 kJ B) -708 kJ C) +708 kJ D) +1420 kJ Answer: A 1.50 mal CHy MOGR KJT4 2mol CHy 15mol CHy 3mol Clz -796.51J
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