Suppose the mating had occurred between homozygous recessive male for a disease and a normal female known to be heterozygous. What would the probabilities be for the following outcomes? 3 offspring in the following order: normal, with disease, normal
Use the factorial equation
n!/x!(n-y)! * (p)x (q)n-x
n = number of events (offspring)
x = number of normal / dominant offspring
n-y =total - number of abnormal / recessive offspring
p = probability of producing a normal/dom
q = probability of producing an abnormal/rec
Mating between the two individuals produces offspring that are show genetic similarity with their parents. This similarity is due to the fact that parents equally contribute to the production of offspring in from of gametes that fuse to form a zygote. These similarities are in the form of characters or traits that are controlled by genes present on chromosomes. In diploid organisms, each chromosome has a copy which means genes have two alternative forms called alleles. When these forms are same the condition is said to be homozygous while the heterozygous term is used when the one form is different from another form. These alleles can be dominant or recessive based on their expression.
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