What would the period of a 1.3m long, 1.00kg pendulum when released from a 10° angle on Earth?
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![*9. What would the period of a 1.3m long, 1.00kg pendulum when released from a 10° angle on Earth?
Explain: Why couldn't you test this directly? Did you need to use Desmos (link at the bottom)? If so, what
were your axis and what data did you use? If not, why not?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F02c99683-a01b-4e64-96f8-7137fedec6c4%2F03443511-edc5-4ce2-a9c6-ee0dd0f980a6%2Fxm9xkn4l_processed.png&w=3840&q=75)
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- A 236 g ball is tied to a string. It is pulled to an O angle of 7.8 and released to swing as a pendulum. A student with a stopwatch finds that 13 oscillations take 18 s. You may want to review (Pages 405 - 407). How long is the string? Express your answer to two significant figures and include the appropriate units. L = μÅ Value Ć Units ?A 0.20 kg ball is tied to a string. It is pulled to an angle of 8.00º and released to swing as a pendulum. At student with a stopwatch finds that 10 oscillations take 12 s. How long is the string? Use g = 10 m/s/s.The figure shows a pendulum with length L that makes a maximum angle 60 with the vertical. Using Newton's Sec- ond Law, it can be shown that the period T (the time for one complete swing) is given by dx |L (=/2 T= 4. VI- k? sin?x where k = sin(}00) and g is the acceleration due to gravity. If L = 1 m and Oo = 42°, use Simpson's Rule with n = 10 to find the period. --