A simple pendulum completes 10 oscillations in 25 second. Another simple pendulum completes 11 oscillations in the same time, at the same place. Compare the lengths of the pendulum.
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Q: A simple pendulum makes 138 complete oscillations in 2.50 min at a location whereg = 9.80 m/s². (a)…
A: Given: The number of cycles is 138. The time taken to complete the 138 cycles is 2.5 min.
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Q: A simple pendulum makes 127 complete oscillations in 3.30 min at a location where g = 9.80 m/s2. (a)…
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Q: A simple pendulum makes 127 complete oscillations in 3.20 min at a location where g = 9.80 m/s2.…
A: Number of oscillations in 3.20 minutes = 127 using , 1 min = 60 seconds Time taken for 127…
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Q: A simple pendulum makes 138 complete oscillations in 2.60 min at a location where g = 9.80 m/s2.…
A: Given data The number of oscillations is given as N = 138. The time taken by one oscillaton is…
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Q: A simple pendulum makes 130 complete oscillations in 2.60 min at a location where g = 9.80 m/s2. (a)…
A: Part(a) PERIOD OF PENDULUM? ans. Since pendulum completes 130 oscillation in=2.6 min=156 s so…
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Q: The period of a simple pendulum is 2.35 s. 1)Determine its length. (Express your answer to three…
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Q: what happens to the period if the angle is halved?
A: The time period remains the same. So, option 2 is correct. 2.Stays the same.
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A: Given information: The time period of the simple pendulum, T=4.00 s
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A: Here, Length of rod= 0.65m g = 9.8m/s^2 Time period of oscillation of simple pendulum is T=…
Q: A person inside an elevator counts that a simple pendulum makes 95 complete oscillations in 2.80…
A: (a) time taken for 95 oscillation = 2.80 min = 168 s time taken for oscillation = 168/95 s…
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A: The total energy of the pendulum is directly related to the square of the amplitude. E∝A2
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Q: What is the frequency
A: 4th option is correct. 1.00 Hz Explanation is in next step.
Q: A pendulum has its amplitude of oscillation decrease to 32.5% of its original value. If it takes…
A: Given data:
Q: A simple pendulum makes 126 complete oscillations in 3.60 min at a location where g = 9.80 m/s2.…
A:
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- The period of a simple pendulum on a planet has been measured as a function of pendulum length. What can be said based on this data? Length (m) T(s) 0.80 1.77 1.00 2.10 1.25 2.24 1.50 2.44 1.75 2.66 2.01 2.84 The free-fall acceleration is about 5.00 m/s^2 on this planet This pendulum may be on Earth This data can not belong to a simple pendulum. The frequency of the pendulum increases with its length The free-fall acceleration on this plane is about 20.0 m/s^2.If you took a pendulum to the moon where g = 1.6 m/s/s, what change would you observe in its period?I use a pendulum consisting only of a wooden rod with a length of 0.4 m. The period (T) of each oscillation is 1.00 s. Using this period, evaluate this equation.
- 5 kilogram object is suspended from a string. The string is 4 meters long. What is the period of the object ting as a pendulum? Express your answer a number of seconds, omitting the unit.A pendulum oscillates is started with an amplitude of 00 = 5.0°. Its e(t) graph is shown at the top of the figure below. If the same pendulum is started at an amplitude of 0o = 10.0°, which curve best describes the motion of the pendulum? 15 50505 100 10 -5 50505 10 15 10 -5 ? ܟ ܘ ܟ ܘ ܩ 5 -5 -10 50505100 -5 MVY original oscillation XXXXXX 02 (b) @o w 4 6 time (s) @ (f) 8 (f) 10A simple pendulum is known to have a period of oscillation, T = 1.55s, Student A uses a digital stopwatch to measure the total time for 5 oscillations and calculates an average period T= 1.25s. Student B uses an analog wristwatch and the same procedure to calculate an average period for the 5 oscillations and finds T=16 s. Which period is more accurate, and why? Show solution.