What would be the major product of the following reaction sequence? The question asks for the major product of a given reaction sequence involving two steps. Below is a detailed transcription and explanation suitable for an educational context.**Question:**What would be the major product of the following reaction sequence?**Reaction Sequence:**1. Reaction with \( \text{Br}_2 \), initiated by \( h\nu \) (light).2. Followed by treatment with \( \text{t-BuOK, t-BuOH,} \) and heat.**Given Compounds:**- The starting compound is a simple cyclohexane derivative with a single methyl group.- Five possible products (I - V) are depicted: - **I:** A cyclohexane with a methyl and a bromine substituent. - **II:** A cyclohexane with a tert-butoxy group (\( \text{Ot-Bu} \)). - **III:** A cyclohexene structure with a single substituent. - **IV:** A cyclohexane with a hydroxyl group. - **V:** A cyclohexane with an \( \text{Ot-Bu} \) substituent on a different position from II.**Options for Major Product:**- I- III- II- V- IVUnderstanding the reaction sequence requires analyzing the mechanistic pathway:1. **First Step:** The \( \text{Br}_2 / h\nu \) reaction suggests a radical halogenation process, likely introducing a bromine atom at the tertiary position of the methyl group. 2. **Second Step:** Treatment with \( \text{t-BuOK, t-BuOH,} \) and heat indicates an elimination or substitution process. This is typical for promoting the formation of an ether or possibly an elimination to form an alkene via E2 elimination.The educational focus should be on:- Radical halogenation under light (producing compound I).- The nucleophilic substitution or elimination process converting the halide into an ether (compound II) or promoting an elimination to form an alkene (compound III).To determine the exact major product, consider the likelihood of elimination vs. substitution under the treatment conditions.

Alkanes in the presence of halogens and light give alkyl halides through a free radical mechanism. Highly substituted alkyl halide would form as a major product. Alkyl halide in the presence of strong base and heat undergo elimination to give alkene. In the presence of strong bilky hindered base, less susbtituted alkene will form as the major product. t-BuOK is strong bulky base. The correct answer is: (B) III