What will this Java statement print? Will it give error? System.out.println(1.0 / 0);
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What will this Java statement print? Will it give error?
System.out.println(1.0 / 0);
Find the output of the given Java statement.
System.out.println(1.0 / 0);
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- Write a program using java and the class main that will prompt the user for a numerator and denominator and returns the fraction reduced. * If the reduced denominator is 1, the reduced answer should a whole number* Improper fractions are fine. You do not need to show mixed number answers.*Feel free to use whichever loop you prefer (while, for or do)*Your program does NOT have to simplify signs (ex negative over negative)Java: I need help writing a method called 'getEvenValue' which keeps prompting user to enter a number until they enter an even number, and then return it back. I'm trying to do this with a while-loop, using no breaks. Could you please help me? This is what I have so far; I'm supposed to edit this for practice in value-producing methods. import java.util.Scanner;public class GP4B{ Scanner in = new Scanner(System.in); public int getValue() { System.out.println("Enter a number. "); int val; val = in.nextInt(); return val; } public static void main(String[] args) { GP4B c = new GP4B(); int x = c.getValue(); System.out.println("The value you entered is " + x); }}This is my program. I need help with the math. import java.util.*;import javax.swing.JOptionPane;public class Craps { public static void main(String[] args) { int Bet, Die; int WinC = 0, LossC = 0, GameC = 0, GameN = 1; double startingBal = 0, curBal = 0; double balD, balDe, balDec, balI, balIn, balInc; char Answer = '\0'; Scanner crapsGame = new Scanner(System.in); System.out.println("Welcome to the Craps Game"); curBal = StartingBal(startingBal); System.out.println("Your starting balance is: $" + curBal); do { System.out.println("Please input your bet for the game>> "); Bet = crapsGame.nextInt(); System.out.println("Game #" + GameN + " Starting with bet of: $" + Bet ); if (Bet < 1 || Bet > curBal) { System.out.println("Invalid bet – Your balance is only: $" + curBal); while (Bet < 1 || Bet > curBal)…
- Dry run the below programs and explain the reasons of output. If there is any error then correct that error with reasoning. class test { int a; int b; test(int i, int j) { a = i; b = j; } void meth(test o) { o.a *= 2; O.b /= 2;}} class Output { public static void main(String args[]) { test obj = new test(10 , 20); obj.meth(obj); System.out.println(obj.a + " " + obj.b); }}javaFix the code so it runs. Take note of what errors are generated by the compiler. What do these errors mean? How do they help you find and fix the errors? import java.util.Scanner; public class Main {public static void main(String[] args) { int numOfBooks = 130;char bookStoreAns; do {System.out.println("Are you at the book store? (y/n)");bookStoreAns = scnr.next().charAt(0);boolean atBookStore; if (bookStoreAns == 'y') {atBookStore = true;} else if (bookStoreAns == 'n') {atBookStore = false;}} while (bookStoreAns != 'y' && bookStoreAns != 'n'); if (atBookStore) {numOfBooks += 4;} System.out.println("I have " + numOfBooks + " books."); }} Can anyone fix this code in Java?
- Someone help me how to solve the error and make program can run . (There are two java file such as main.java and payment.java) /*** Assignment Food Ordering system.java** Ordering system application*/package orderingsystem; import java.util.Scanner; public class Orderingsystem {public static Scanner input = new Scanner(System.in);public static String again;public static int choose,quantity=1;public static double total=0,pay;public static void menu(){System.out.println("\t\t\t\t+=======================================+");System.out.println("\t\t\t\t+ Fruit Juice Menu +");System.out.println("\t\t\t\t+=======================================+");System.out.println("\t\t\t\t+ 1. Aloe vera RM 19 +");System.out.println("\t\t\t\t+ 2. Appple Juice RM 18 +");System.out.println("\t\t\t\t+ 3. Banana Juice RM 20 +");System.out.println("\t\t\t\t+ 4. Cancel +");System.out.println("\t\t\t\t+=======================================+");}public static void order (){System.out.println("Press 1 to Aloe…Write input value for i, j, and k for a test case. The test case should be able to reveal error(s) by making the following Java code fail or return mathematically incorrect value. You only needs to give a single test case -- i.e., one value for each i,j, and k. static double invalidInput(int i, int j, int k) { if (j != 0) return i / j + k; else return i + k; } i= Enter your answer here j= Enter your answer here k = Enter your answer hereCan you write Java code according to the requirements?
- public static int test(int n, int k) { if (k == 0 || k == n) { return 1; } else if (k>n) { return 0; } else { return test(n-1, k-1) + test(n-1, k); } ww For each of the following calls, indicate the output that is produ test(7,5); test(6,4); test(4,5); test(8,3); test(5,5);Below is the code in Java to add 2 binary Numbers: Both the codes execute, Could someone explain which code is much efficient and the differences between both codes, By testing with different inputs. public void add(BinaryNumber aBinaryNumber) { Code 1:if(getLength() != aBinaryNumber.getLength()) { System.out.println("Lengths of numbers to be added is different. ");}else { int carry = 0; for(int i = 0; i < data.length; i++) { int z = carry + getDigit(i) + aBinaryNumber.getDigit(i); if(z >= 10) { z = z - 10; carry = 1; } else { carry = 0; } data[i] = z; } if(carry != 0) { overFlow = true; }} Code 2: int data1[] = new int[aBinaryNumber.getLength()]; data1 = aBinaryNumber.getBinary(); int carry = 0; if(data.length == data1.length) { for(int i=0; i<data.length; i++) { int t = (carry + data[i] + data1[i]); if(t == 0) { data[i] = 0;…Please code in java