What will be the power of a girl who can run with a velocity 4 m/s for 20 seconds. The mass of the girl is 50 kg ? 20 W 30 W None of the options available O 10 W 40 W

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Chapter1: Units, Trigonometry. And Vectors
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**Question:**
What will be the power of a girl who can run with a velocity of 4 m/s for 20 seconds? The mass of the girl is 50 kg.

**Options:**
- 20 W
- 30 W
- None of the options available
- 10 W
- 40 W

**Explanation:**

To calculate the power, we need to determine the kinetic energy and then use it to find power. The kinetic energy (KE) of the girl can be calculated using the formula:

\[ KE = \frac{1}{2} m v^2 \]

where:
- \( m = 50 \) kg (mass of the girl)
- \( v = 4 \) m/s (velocity)

Substituting the values:

\[ KE = \frac{1}{2} \times 50 \, \text{kg} \times (4 \, \text{m/s})^2 \]
\[ KE = \frac{1}{2} \times 50 \times 16 \]
\[ KE = 25 \times 16 \]
\[ KE = 400 \, \text{Joules} \]

Power is calculated using the formula:

\[ \text{Power} = \frac{\text{Work done}}{\text{Time}} = \frac{\text{Kinetic Energy}}{\text{Time}} \]

Given time is 20 seconds:

\[ \text{Power} = \frac{400 \, \text{Joules}}{20 \, \text{seconds}} \]
\[ \text{Power} = 20 \, \text{Watts} \]

**Correct Answer:**
- 20 W
Transcribed Image Text:**Question:** What will be the power of a girl who can run with a velocity of 4 m/s for 20 seconds? The mass of the girl is 50 kg. **Options:** - 20 W - 30 W - None of the options available - 10 W - 40 W **Explanation:** To calculate the power, we need to determine the kinetic energy and then use it to find power. The kinetic energy (KE) of the girl can be calculated using the formula: \[ KE = \frac{1}{2} m v^2 \] where: - \( m = 50 \) kg (mass of the girl) - \( v = 4 \) m/s (velocity) Substituting the values: \[ KE = \frac{1}{2} \times 50 \, \text{kg} \times (4 \, \text{m/s})^2 \] \[ KE = \frac{1}{2} \times 50 \times 16 \] \[ KE = 25 \times 16 \] \[ KE = 400 \, \text{Joules} \] Power is calculated using the formula: \[ \text{Power} = \frac{\text{Work done}}{\text{Time}} = \frac{\text{Kinetic Energy}}{\text{Time}} \] Given time is 20 seconds: \[ \text{Power} = \frac{400 \, \text{Joules}}{20 \, \text{seconds}} \] \[ \text{Power} = 20 \, \text{Watts} \] **Correct Answer:** - 20 W
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