What will be the output of the following C code? #include #include #include int main() { time_t ct; time(&ct); printf("%s\n",ctime(&ct)); } a) only current date b) only current date and current time c) current date, current time and the day of the week d) only current time
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What will be the output of the following C code?
#include<stdio.h>
#include<stdlib.h>
#include<time.h>
int main()
{
time_t ct;
time(&ct);
printf("%s\n",ctime(&ct));
}
a) only current date
b) only current date and current time
c) current date, current time and the day of the week
d) only current time
This question asks to find the output of the following program.
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- c++ programming need code for the sample run/output below there are no restrictions with coding as long as it is under c++ you may use array and OOP and other structures if needed but not files make the code as simple and basic as it can get whenever possible also please insert pseudocodes for better understanding If you are the previous person who answered this, I have made revisions. Please change accordingly Thank you! Sample Run/Output: STUDENT ENROLLMENT SYSTEM Registration Records Exit Choose: [1/2/3] Enter number of choice: *user input *if 1. Registration New Student Returning Student choose: [a/b] Enter letter of choice: *user input *if a. New Student Enter Name: *user input Enter General Average: *user input *if average is less than 75, print “cannot proceed”, end program *else, continue and print “You may proceed with registration” REGISTRATION Enter Age: *user input Enter Sex: *user input Enter Address: *user input Enter…Given C code: #include <stdio.h>typedef struct compound { float realNumber; float imaginaryNumber;} compound; compound add(compound n1, compound n2); int main() { compound n1, n2, temp; printf("For the first compound number \n"); printf("Enter the real and imaginary parts: "); scanf("%f %f", &n1.realNumber, &n1.imaginaryNumber); printf("\nFor the second compound number \n"); printf("Enter the real and imaginary parts: "); scanf("%f %f", &n2.realNumber, &n2.imaginaryNumber); temp = add(n1, n2); printf("Sum = %.1f + %.1fi", temp.realNumber, temp.imaginaryNumber); return 0;} compound add(compound n1, compound n2) { compound temp; temp.realNumber = n1.realNumber + n2.realNumber; temp.imaginaryNumber = n1.imaginaryNumber + n2.imaginaryNumber; return (temp);} Task: Please change the C program above to execute complicated numeral multiplication. Hint: (e+fi)(g+hi) = (eg−fh) + (eh+fg)iPLease fix my code __ #include<stdio.h> main() { char name[50]; int grades; printf ("enteryourlastname"); scanf ("%c", &lastname); printf ("enteryourfirstname"); scanf ("%c", &firstname); printf ("enteryourprelimgrade"); scanf ("%d", &prelimgrade); printf ("enteryourmidtermgrade"); scanf ("%d", &midtermgrade); printf ("enteryourfinalgrade"); scanf ("%d", &finalgrade); int Average=(prelim+midterm+finals/3); if (grade>=75) printf ("Congratulations you passed the subject"); else printf ("Sorry you failed the subject"); getche(); return 0; }
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