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What will be the molecular diffusion coefficient of naphthalene vapor in air at 0 °C and 1 Atm pressure; a) Chapman-Enskog b) Estimate from Fuller, Schettler and Giddings (Atomic diffusion volumes) Equations. Compare the values you found with the experimental value of 0.0513 cm2 /s. The critical temperature and volume of naphthalene are 748.4 K and 408 cm3/gmol. The critical temperature and volume of air are 132.5 K and 90.52 cm3 /gmol. MNaphthalene=128.16 and MHair=29

What will be the molecular diffusion coefficient of naphthalene vapor in air at 0 °C and 1 Atm pressure; a) Chapman-Enskog b) Estimate from Fuller, Schettler and Giddings (Atomic diffusion volumes) Equations. Compare the values you found with the experimental value of 0.0513 cm2 /s. The critical temperature and volume of naphthalene are 748.4 K and 408 cm3/gmol. The critical temperature and volume of air are 132.5 K and 90.52 cm3 /gmol. MNaphthalene=128.16 and MHair=29

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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What will be the molecular diffusion coefficient of naphthalene vapor in air at 0 °C and 1 Atm pressure;
a) Chapman-Enskog
b) Estimate from Fuller, Schettler and Giddings (Atomic diffusion volumes) Equations. Compare the values you found with the experimental value of 0.0513 cm2 /s.
The critical temperature and volume of naphthalene are 748.4 K and 408 cm3/gmol. The critical temperature and volume of air are 132.5 K and 90.52 cm3 /gmol.
MNaphthalene=128.16 and MHair=29

A = 8.33Vc¹/3 = 11.8Vb¹/3 E k 0.75Tc 1.21Tb
Transcribed Image Text:A = 8.33Vc¹/3 = 11.8Vb¹/3 E k 0.75Tc 1.21Tb
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