What will be the maximum speed of a car on a road turn of radius 30 m, if the coefficient of friction between the tyres and the road is 0.4 ? (Take g = 9.8 m/s²) (a) 10.84 m/s (c) 8.84 m/s (d) (b) 9.84 m/s 6.84 m/s
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- A 1.5kg rock is tied to the end of a 1.25m string and is swung in a vertical circle at a constant speed of 4.5 m·s−1. If the string breaks when the tension is 135 N, calculate the maximum speed that the rock can be swung without breaking the string?A race car travels 76 m/s around a circulartrack of radius 159 m What is the magnitude of the resultantforce on the 1600 kg driver and his car ifthe car does not slip?Answer in units of kN.A vehicle with a mass of 2.1×10³ kg is driving at a speed of 61 km/h around a level roadway with a curvature radius of 61 meters, just staying on the roadway (i.e., driving at the maximum safe speed for this turn and the tire treads). What is the coefficient of friction between the tires and the road? (Hint: Watch your units above.) Answer: μ = (no units)
- A banked roadway of radius 200m is designed for traffic moving at a maximum speed of 18m/s. Ignoring the friction, the angle at which the roadway is banked is closest to. 13 degrees 9 degrees 18 degrees 7 degreesA car of massm travels around a flat, circular curve of radius r at the fastest possible speed, v = 13.5 m/s without sliding off. The car and road have a coefficient of friction, between them. If the car wishes to take the turn at 2.4x the velocity, by what factor would the radius need to increase (so the car doesn't slide off) ? Give your answer to 1 decimal place.How large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 85m at a speed of 26.4 m/s? Assume that the tires are not slipping , but about to break free. (Answer =0.84)
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