Differentiate the function. y = ex + 3 + 8
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the ques
skipped part.
Tutorial Exercise
Differentiate the function.
y = ex + 3 +8
Step 1
We first note that we can rewrite the function using the laws of exponents as follows.
y = ex + 3 + 8
11
1) (e³).
+ 8
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Follow-up Question
![We have rewritten the given function as e³(ex) + 8, and we wish to find the derivative y'. In other words, we need to find the following.
y' = d (e³(ex) + 8)
Recall the sum rule, which states that if f and g are both differentiable, then the following is true.
d
d
d
dx [f(x) + g(x)] = f(x) -g(x)
+
dx
dx
Applying this rule allows us to rewrite as follows.
y' = d (e³(ex) + 8)
dx
= & (e²³(er)) + ( et + 3
dx
X](https://content.bartleby.com/qna-images/question/9763047e-9567-4a9b-b6af-b6a297414ad2/eb8e320c-dc2a-4da1-97ae-d062e40efebc/qxfmct_processed.png)
Transcribed Image Text:We have rewritten the given function as e³(ex) + 8, and we wish to find the derivative y'. In other words, we need to find the following.
y' = d (e³(ex) + 8)
Recall the sum rule, which states that if f and g are both differentiable, then the following is true.
d
d
d
dx [f(x) + g(x)] = f(x) -g(x)
+
dx
dx
Applying this rule allows us to rewrite as follows.
y' = d (e³(ex) + 8)
dx
= & (e²³(er)) + ( et + 3
dx
X
Solution
by Bartleby ExpertFollow-up Question
what will be the answer that is inserted in the blank of the pervious qustion
Solution
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