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Express your answer in joules per kelvin to one decimal place. C2H2(g)+H2(g)→C2H4(g)C2H2(g)+H2(g)→C2H4(g)   C(s,diamond)+H2O(g)→CO(g)+H2(g)C(s,diamond)+H2O(g)→CO(g)+H2(g)   CO(g)+H2O(g)→H2(g)+CO2(g)CO(g)+H2O(g)→H2(g)+CO2(g)    4NH3(g)+5O2(g)→4NO(g)+6H2O(l)

Express your answer in joules per kelvin to one decimal place. C2H2(g)+H2(g)→C2H4(g)C2H2(g)+H2(g)→C2H4(g)   C(s,diamond)+H2O(g)→CO(g)+H2(g)C(s,diamond)+H2O(g)→CO(g)+H2(g)   CO(g)+H2O(g)→H2(g)+CO2(g)CO(g)+H2O(g)→H2(g)+CO2(g)    4NH3(g)+5O2(g)→4NO(g)+6H2O(l)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Express your answer in joules per kelvin to one decimal place.
C2H2(g)+H2(g)→C2H4(g)C2H2(g)+H2(g)→C2H4(g)
 
C(s,diamond)+H2O(g)→CO(g)+H2(g)C(s,diamond)+H2O(g)→CO(g)+H2(g)
 
CO(g)+H2O(g)→H2(g)+CO2(g)CO(g)+H2O(g)→H2(g)+CO2(g)
 
 4NH3(g)+5O2(g)→4NO(g)+6H2O(l)
 
 
MISSED THIS? Watch IWE 18.5; Read Section 18.7. You can click on the Review link to access the section in your e Text. Use data from the table below to calculate ASn for each of the reactions. S° (J/(mol · K)) Substance C(s, diamond) 2.4 C(s, graphite) 5.7 C2H2 (g) 200.9 C2H4 (g) 219.3 CO(g) 197.7 CO2 (g) 213.8 H2 (g) 130.7 H2O(g) 188.8 H2O(1) 70.0 NH3 (g) 192.8 O2 (g) 205.2 NO(g) 210.8
Transcribed Image Text:MISSED THIS? Watch IWE 18.5; Read Section 18.7. You can click on the Review link to access the section in your e Text. Use data from the table below to calculate ASn for each of the reactions. S° (J/(mol · K)) Substance C(s, diamond) 2.4 C(s, graphite) 5.7 C2H2 (g) 200.9 C2H4 (g) 219.3 CO(g) 197.7 CO2 (g) 213.8 H2 (g) 130.7 H2O(g) 188.8 H2O(1) 70.0 NH3 (g) 192.8 O2 (g) 205.2 NO(g) 210.8
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