What volume of a 0.101 M barium hydroxide solution is required to neutralize 25.0 mL of a 0.147 M hydrobromic acid solution? mL barium hydroxide Submit Answer Retry Entire Group 9 more group attempts remaining

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### Chemistry Neutralization Problem

**Problem Statement:**
What volume of a 0.101 M barium hydroxide solution is required to neutralize 25.0 mL of a 0.147 M hydrobromic acid solution?

**Answer Box:**
\[ \_\_\_\_\_\_\_\_ \text{ mL barium hydroxide} \]

**Buttons:**
- **Submit Answer**
- **Retry Entire Group**

**Remaining Attempts:**
- 9 more group attempts remaining.

### Explanation

This problem involves the concept of a neutralization reaction, where an acid reacts with a base to produce water and a salt. The task is to determine the volume of barium hydroxide (a base) needed to completely neutralize a given volume and molarity of hydrobromic acid (an acid).

### Extended Support

1. **Understanding the Reaction:**
   - The balanced neutralization reaction between barium hydroxide \((\text{Ba(OH)}_2)\) and hydrobromic acid \((\text{HBr})\) can be represented as:
   \[
   \text{Ba(OH)}_2 + 2\text{HBr} \rightarrow \text{BaBr}_2 + 2\text{H}_2\text{O}
   \]

2. **Reaction Stoichiometry:**
   - According to the balanced equation, one mole of barium hydroxide reacts with two moles of hydrobromic acid.

3. **Calculations:**
   - Find the moles of hydrobromic acid:
     \[
     \text{Moles of HBr} = \text{Molarity of HBr} \times \text{Volume of HBr} = 0.147 \text{ M} \times 0.025 \text{ L} = 0.003675 \text{ moles}
     \]
   - Using the stoichiometry, calculate the moles of barium hydroxide required:
     \[
     \text{Moles of Ba(OH)}_2 = \frac{\text{Moles of HBr}}{2} = \frac{0.003675}{2} = 0.0018375 \text{ moles}
     \]
   - Finally, determine the volume of barium hydroxide solution needed:
     \[
     \text
Transcribed Image Text:### Chemistry Neutralization Problem **Problem Statement:** What volume of a 0.101 M barium hydroxide solution is required to neutralize 25.0 mL of a 0.147 M hydrobromic acid solution? **Answer Box:** \[ \_\_\_\_\_\_\_\_ \text{ mL barium hydroxide} \] **Buttons:** - **Submit Answer** - **Retry Entire Group** **Remaining Attempts:** - 9 more group attempts remaining. ### Explanation This problem involves the concept of a neutralization reaction, where an acid reacts with a base to produce water and a salt. The task is to determine the volume of barium hydroxide (a base) needed to completely neutralize a given volume and molarity of hydrobromic acid (an acid). ### Extended Support 1. **Understanding the Reaction:** - The balanced neutralization reaction between barium hydroxide \((\text{Ba(OH)}_2)\) and hydrobromic acid \((\text{HBr})\) can be represented as: \[ \text{Ba(OH)}_2 + 2\text{HBr} \rightarrow \text{BaBr}_2 + 2\text{H}_2\text{O} \] 2. **Reaction Stoichiometry:** - According to the balanced equation, one mole of barium hydroxide reacts with two moles of hydrobromic acid. 3. **Calculations:** - Find the moles of hydrobromic acid: \[ \text{Moles of HBr} = \text{Molarity of HBr} \times \text{Volume of HBr} = 0.147 \text{ M} \times 0.025 \text{ L} = 0.003675 \text{ moles} \] - Using the stoichiometry, calculate the moles of barium hydroxide required: \[ \text{Moles of Ba(OH)}_2 = \frac{\text{Moles of HBr}}{2} = \frac{0.003675}{2} = 0.0018375 \text{ moles} \] - Finally, determine the volume of barium hydroxide solution needed: \[ \text
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