What volume of a 0.101 M barium hydroxide solution is required to neutralize 25.0 mL of a 0.147 M hydrobromic acid solution? mL barium hydroxide Submit Answer Retry Entire Group 9 more group attempts remaining
What volume of a 0.101 M barium hydroxide solution is required to neutralize 25.0 mL of a 0.147 M hydrobromic acid solution? mL barium hydroxide Submit Answer Retry Entire Group 9 more group attempts remaining
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Chemistry Neutralization Problem
**Problem Statement:**
What volume of a 0.101 M barium hydroxide solution is required to neutralize 25.0 mL of a 0.147 M hydrobromic acid solution?
**Answer Box:**
\[ \_\_\_\_\_\_\_\_ \text{ mL barium hydroxide} \]
**Buttons:**
- **Submit Answer**
- **Retry Entire Group**
**Remaining Attempts:**
- 9 more group attempts remaining.
### Explanation
This problem involves the concept of a neutralization reaction, where an acid reacts with a base to produce water and a salt. The task is to determine the volume of barium hydroxide (a base) needed to completely neutralize a given volume and molarity of hydrobromic acid (an acid).
### Extended Support
1. **Understanding the Reaction:**
- The balanced neutralization reaction between barium hydroxide \((\text{Ba(OH)}_2)\) and hydrobromic acid \((\text{HBr})\) can be represented as:
\[
\text{Ba(OH)}_2 + 2\text{HBr} \rightarrow \text{BaBr}_2 + 2\text{H}_2\text{O}
\]
2. **Reaction Stoichiometry:**
- According to the balanced equation, one mole of barium hydroxide reacts with two moles of hydrobromic acid.
3. **Calculations:**
- Find the moles of hydrobromic acid:
\[
\text{Moles of HBr} = \text{Molarity of HBr} \times \text{Volume of HBr} = 0.147 \text{ M} \times 0.025 \text{ L} = 0.003675 \text{ moles}
\]
- Using the stoichiometry, calculate the moles of barium hydroxide required:
\[
\text{Moles of Ba(OH)}_2 = \frac{\text{Moles of HBr}}{2} = \frac{0.003675}{2} = 0.0018375 \text{ moles}
\]
- Finally, determine the volume of barium hydroxide solution needed:
\[
\text](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9bc6dc7-2424-4f69-956a-285f3752d785%2F542911a6-5756-4eae-84cf-9e72524a0341%2F9m3cec_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Chemistry Neutralization Problem
**Problem Statement:**
What volume of a 0.101 M barium hydroxide solution is required to neutralize 25.0 mL of a 0.147 M hydrobromic acid solution?
**Answer Box:**
\[ \_\_\_\_\_\_\_\_ \text{ mL barium hydroxide} \]
**Buttons:**
- **Submit Answer**
- **Retry Entire Group**
**Remaining Attempts:**
- 9 more group attempts remaining.
### Explanation
This problem involves the concept of a neutralization reaction, where an acid reacts with a base to produce water and a salt. The task is to determine the volume of barium hydroxide (a base) needed to completely neutralize a given volume and molarity of hydrobromic acid (an acid).
### Extended Support
1. **Understanding the Reaction:**
- The balanced neutralization reaction between barium hydroxide \((\text{Ba(OH)}_2)\) and hydrobromic acid \((\text{HBr})\) can be represented as:
\[
\text{Ba(OH)}_2 + 2\text{HBr} \rightarrow \text{BaBr}_2 + 2\text{H}_2\text{O}
\]
2. **Reaction Stoichiometry:**
- According to the balanced equation, one mole of barium hydroxide reacts with two moles of hydrobromic acid.
3. **Calculations:**
- Find the moles of hydrobromic acid:
\[
\text{Moles of HBr} = \text{Molarity of HBr} \times \text{Volume of HBr} = 0.147 \text{ M} \times 0.025 \text{ L} = 0.003675 \text{ moles}
\]
- Using the stoichiometry, calculate the moles of barium hydroxide required:
\[
\text{Moles of Ba(OH)}_2 = \frac{\text{Moles of HBr}}{2} = \frac{0.003675}{2} = 0.0018375 \text{ moles}
\]
- Finally, determine the volume of barium hydroxide solution needed:
\[
\text
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