4) A student wishes to check the amount of HCI found in a bottle in lab. On the label of the bottle, the concentration of HCI is expressed as mg per liter of solution. Help her determine how much of her NaOH solution will be required to titrate 50.00 mL of the solution in the assigned option below. A HCl + NAOH → Nac + Hz ОРТION How many mL of Ob27 ?M NAOH will be required to titrate 50.00 mL of the HCI labeled y51 mg HCI/L? Hint: a) Change mg/L to mole/L of HCI b) Find moles of HCI c) Convert to moles of NaOH d) Find mL of NaOH
4) A student wishes to check the amount of HCI found in a bottle in lab. On the label of the bottle, the concentration of HCI is expressed as mg per liter of solution. Help her determine how much of her NaOH solution will be required to titrate 50.00 mL of the solution in the assigned option below. A HCl + NAOH → Nac + Hz ОРТION How many mL of Ob27 ?M NAOH will be required to titrate 50.00 mL of the HCI labeled y51 mg HCI/L? Hint: a) Change mg/L to mole/L of HCI b) Find moles of HCI c) Convert to moles of NaOH d) Find mL of NaOH
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Determination of Stoichiometric Coeffieients
Out-of-Class Exercise
4) A student wishes to check the amount of HCl found in a bottle in lab. On the Jabel of the
bottle, the concentration of HCl is expressed as mg per liter of solution. Help her determine how
much of her NAOH solution will be required to titrate 50.00 mL of the solution in the assigned
option below.
A
HI + NAOH → Nacl t HzO
OPTION
How many mL of O-b27 ³ M NAOH will be required to titrate 50.00 mL of the HCI labeled
491 mg HCI/L?
Hint: a) Change mg/L to mole/L of HCl
b) Find moles of HCI
c) Convert to moles of NaOH
d) Find mL of NaOH
mal of Hel: 451mytHCI x D.00lg HCly Lmel 0.us1
Ing
1. 24 x10
0.451
451 my HCI x D.001lg Hcly I mol
36 51g
3451
HCI
= 0.01 235
%3D
l.01
35.5
mol NAOH = 1.24X10-2
mul HLI X
I mul NaUH
I mol tHl
= \, 24 x10-2 mol NAOH
Xavier University of Louisiana
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