Answered: What volume of \$0.340\$ M…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The balanced equation for the neutralization reaction of aqueous \$\ce{H2SO4}\$ with aqueous \$\ce{KOH}\$ is shown.

$$\ce{H_2 SO_4 (aq) +2KOH (aq) -> 2H_2 O (l) +K_2 SO_4 (aq) }$$

What volume of \$0.340\$ M \$\ce{KOH}\$ is needed to react completely with \$15.7\$ mL of \$0.215\$ M \$\ce{H2SO4}\$?

volume: into \$ \text{mL} \$

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Introduction

Molarity is defined as “the mole of the solute per unit volume of the solution”. It is represented by M and has the units of mol/L. The molarity equation is given as follows:

M₁V₁ = M₂V₂

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