**Question:**What volume of 0.0432 M calcium hydroxide is required to neutralize 34.20 mL of 0.0355 M nitric acid?**Answer:**Volume = ____ mL---**Explanation:**This problem involves a stoichiometric calculation for a neutralization reaction between calcium hydroxide (\( \text{Ca(OH)}_2 \)), a base, and nitric acid (\( \text{HNO}_3 \)), an acid. The reaction can be represented as:\[ \text{Ca(OH)}_2 + 2 \text{HNO}_3 \rightarrow \text{Ca(NO}_3\text{)}_2 + 2 \text{H}_2\text{O} \]The goal is to find the volume of the calcium hydroxide solution needed to completely neutralize the given volume and concentration of nitric acid. Use the formula:\[ \text{M}_1 \times \text{V}_1 \times \text{n}_1 = \text{M}_2 \times \text{V}_2 \times \text{n}_2 \]Where:- \( \text{M}_1 \) and \( \text{V}_1 \) are the molarity and volume of \(\text{HNO}_3\), respectively.- \( \text{M}_2 \) and \( \text{V}_2 \) are the molarity and volume of \(\text{Ca(OH)}_2\), respectively.- \( \text{n}_1 \) and \( \text{n}_2 \) are the stoichiometric coefficients (from the balanced equation).Here’s how you would solve it:1. Calculate the moles of nitric acid.2. Use the stoichiometric coefficients to find the moles of calcium hydroxide needed.3. Calculate the volume of the calcium hydroxide solution required using its molarity.

In acid-base neutralization reaction number of the equivalent of acid and base reacted with each other will be the same.[Ca(OH)2] = 0.0432 M V Ba(OH)2 = V ml n Ba(OH)2= 0.0432 M xVml = 0.0432V m mole [HNO3 ] = 0.0355 M V HCl = 34.20 ml nHCl= 0.0355 M x34.20 ml = 1.2141 m mole the balance chemical reaction for this acid base neutralization reaction is, Ca(OH)₂ (aq) + 2 HNO3 (aq) → Ca(NO3)₂ (s) + 2 H2O(l) I 0.0432V m mole 1.2141 m mole 0 0 C -0.607 m mole -1.2141 m mole +0.607 m mole +1.2141 m mole E 0 mmol 0 mmol 0.607m mole 70 m mole Number of moles of Ca(OH)₂(s) reacted = 0.607 m mol 0.0432V = 0.607 m mole Or V = 0.607 /0.0432mL = 14.052 mL Volume of Ba(OH)₂(s) reacted = 14 mL (approx.)

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What volume of 0.0432 M calcium hydroxide is required to neutralize 34.20 mL of 0.0355 M nitric acid? Volume mL %3D

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter15: Solutions

Section: Chapter Questions

Problem 39QAP: 39. Standard solutions of calcium ion used to test for water hardness are prepared by dissolving...

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