What quantity of moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical reaction: 2 Al(s) + 3 H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3 H₂(g)

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What quantity of moles of H₂SO₄ are required to completely react with 7.20 mol of Al according to the balanced chemical reaction:

2 Al(s) + 3 H₂SO₄(aq) → Al₂(SO₄)₃(aq) + 3 H₂(g)

**Stoichiometry Calculation Exercise**

**Objective:** Determine the quantity of moles of \(\text{H}_2\text{SO}_4\) required to completely react with 7.20 moles of Al according to the balanced chemical reaction:

\[ 2 \text{Al}(s) + 3 \text{H}_2\text{SO}_4(aq) \rightarrow \text{Al}_2(\text{SO}_4)_3(aq) + 3 \text{H}_2(g) \]

**Step-by-Step Guide:**

1. **Identify the Initial Amount:**
   - The starting quantity provided is 7.20 moles of Al.

2. **Determine the Relationship:**
   - From the balanced equation, 2 moles of Al react with 3 moles of \(\text{H}_2\text{SO}_4\).

3. **Calculate Required Moles:**
   - Use the stoichiometric relationships from the equation to calculate the required moles of \(\text{H}_2\text{SO}_4\).

**Calculation Process:**

- **Starting Amount Section:**
  - Enter 7.20 moles of Al in the appropriate field.

- **Add Factor Section:**
  - Utilize the stoichiometric ratio (3 moles \(\text{H}_2\text{SO}_4\) for every 2 moles of Al).
  - Input necessary coefficients to multiply and calculate moles of \(\text{H}_2\text{SO}_4\).

- **Answer Box:**
  - The solution provides the resultant moles of \(\text{H}_2\text{SO}_4\) required.

- **Reset:**
  - Optionally, use the reset button to start the calculation over if needed.

**Tools Provided:**

- **Button Values:** Represent various quantities and unit conversions, including:
  - Moles and grams for relevant substances.
  - Molecular weights and constants such as Avogadro's number.

This exercise helps visualize and practice stoichiometry, crucial for understanding chemical reactions and quantitative relationships between reactants and products.
Transcribed Image Text:**Stoichiometry Calculation Exercise** **Objective:** Determine the quantity of moles of \(\text{H}_2\text{SO}_4\) required to completely react with 7.20 moles of Al according to the balanced chemical reaction: \[ 2 \text{Al}(s) + 3 \text{H}_2\text{SO}_4(aq) \rightarrow \text{Al}_2(\text{SO}_4)_3(aq) + 3 \text{H}_2(g) \] **Step-by-Step Guide:** 1. **Identify the Initial Amount:** - The starting quantity provided is 7.20 moles of Al. 2. **Determine the Relationship:** - From the balanced equation, 2 moles of Al react with 3 moles of \(\text{H}_2\text{SO}_4\). 3. **Calculate Required Moles:** - Use the stoichiometric relationships from the equation to calculate the required moles of \(\text{H}_2\text{SO}_4\). **Calculation Process:** - **Starting Amount Section:** - Enter 7.20 moles of Al in the appropriate field. - **Add Factor Section:** - Utilize the stoichiometric ratio (3 moles \(\text{H}_2\text{SO}_4\) for every 2 moles of Al). - Input necessary coefficients to multiply and calculate moles of \(\text{H}_2\text{SO}_4\). - **Answer Box:** - The solution provides the resultant moles of \(\text{H}_2\text{SO}_4\) required. - **Reset:** - Optionally, use the reset button to start the calculation over if needed. **Tools Provided:** - **Button Values:** Represent various quantities and unit conversions, including: - Moles and grams for relevant substances. - Molecular weights and constants such as Avogadro's number. This exercise helps visualize and practice stoichiometry, crucial for understanding chemical reactions and quantitative relationships between reactants and products.
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