What quantity in moles of precipitate will be formed when 85.0 nL of 0.300 M AgNO3 is reacted with excess Cal₂ in the following chemical reaction? 2 AgNO3 (aq) + Cal₂ (aq) → 2 Agl (s) - Ca(NO3)2 (aq)

Q: What is the mass in grams of precipitate formed when 250.0 mL of 0.310 M ZnCI, is mixed with excess…

A: Here excess of KOH is given; it means the limiting agent is ZnCl2. So ZnCl2 will decide the mass of…

Q: How many moles of precipitate will be formed when 260.0 mL of 0.200 M NaBr is reacted with excess…

A: Given : Molarity of NaBr = 0.200 M              Volume of solution = 260 mL To find : moles of PbBr2…

Q: 0.7532 g of copper turnings (molar mass: 63.546 g∙mol–1) are reacted with excess nitric acid.…

A: Disclaimer: In order to obtain copper sulfate the acid used in excess should be sulfuric acid and…

Q: What mass of precipitate (in g) is formed when 72.8 mL of 0.500 M FeCl₃ reacts with excess AgNO₃ in…

A: From the reaction it is clear that 1 mole FeCl3 reacts with 3 moles AgNO3 to give 3 moles AgCl.…

Q: If 785 mL of 0.350 M AgNO3 is added to 435 mL of 0.250 м CaBr₂, how many moles of AgBr precipitate…

A: The objective of this question is to determine the number of moles of AgBr that will precipitate…

Q: Determine the mass of precipitate, in grams, that forms when 55.3 mL of 0.0424 M Na2CO3 reacts with…

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Q: What mass of precipitate (in g) is formed when 85.7 mL of 0.500 M FeCl₃ reacts with excess AgNO₃ in…

A: Given precipitation reaction; FeCl3 (aq) + 3 AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq) Given volume of…

Q: How many grams of precipitate are formed when 75 mL of 0.50 M FeCl₃ reacts with excess AgNO₃ in the…

A: Given, volume of FeCl₃ = 75 mL            Concentration of FeCl₃  = 0.50 M Now, number of moles of…

Q: What quantity in moles of precipitate will be formed when 272.5 mL of 0.400 M NaI is reacted with…

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Q: How many liters of 0.15 M KCl solution are needed to completely react with 5.53 L of 0. 175 M lead…

A: The balanced chemical reaction is written below.2KCl (aq) + Pb(NO3)2 (aq) → PbCl2 (s) + 2KNO3…

Q: How many grams of precipitate are formed when 250.0 mL of 0.110 M ZnCl₂ is mixed with excess KOH in…

A: Zn(OH)2 is the precipitate in this reaction.Molecular mass of Zn(OH)2  = 99.424 g/mol

Q: What mass of precipitate (in g) is formed when 250.0 mL of 0.200 M CoCl₂ is mixed with excess KOH in…

A: The balanced equation is given as;   CoCl2(aq) + 2 KOH (aq)→Co(OH)2(s)+2KCl(aq) From the question,…

Q: Complete a reaction table (in millimoles) for the net reaction resulting when 41.4 mL of 0.0830 M…

A: A question based on mole concept. A set of data for a balanced equation is given based on which the…

Q: What quantity in moles of precipitate will be formed when 77.1 mL of 0.150 M AgNO3 is reacted with…

A:

Q: What quantity in moles of precipitate will be formed when 73.7 mL of 0.150 M AgNO₃ is reacted with…

A:

Q: AgNO₃(aq) → 3 AgCl(s) + Fe(NO₃)₃(aq)

A: This can be solved by balancing the equation.required solution is given below

Q: If 19.5 g of NaOH is added to 0.800 L of 1.00 M Zn(NO₃)₂, how many grams of Zn(OH)₂ will be formed…

A: Given, Mass of NaOH = 19.5 g            Molarity of Zn(NO₃)₂ = 1.00 M            Volume of Zn(NO₃)₂…

Q: According to the following reaction, how many moles of Fe(OH)2 can form from 175.0 mL of 0.227 M…

A: Moles of LiOH used =Molarity of LiOH×Volume of LiOH= 0.227 mol/L×175.0×10-3L=0.0397 mol

Q: What quantity in moles of precipitate will be formed when 168.0 mL of 0.350 M NaCl is reacted with…

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Q: How many moles of precipitate will be formed

A: Molarity = number of moles/volume of solution (in L)  Number of moles = molarity × volume (in L)

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 23.0 mL of…

A: Number of moles of substance=Concentration of substance x Volume of substanceFor…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.500 M Cu(NO3)2 reacts with 20.0 mL of…

A: Here we are required to find the mass of precipitate formed during the given reaction  1L=1000 ml.

Q: How many moles of precipitate will be formed when 81.2 mL of 0.300 M AgNO₃ is reacted with excess…

A: According to the balanced chemical equation, 2 moles of AgNO3 gives 2 moles of AgI (precipitate).…

Q: How many moles of precipitate will be formed when 80.0 mL of 2.00 M NaI is reacted with 100.0 mL of…

A: 2 NaI (aq) + Pb(NO₃)₂ (aq) → PbI₂ (s) + 2 NaNO₃ (aq) To determining limiting reactant ; Firstly we…

Q: What quantity in moles of precipitate will be formed when 70.0 mL of 0.150 M AgNO₃ is reacted with…

A: Consider the given reaction is as follows; 2 AgNO3 (aq) + CaCl2 (aq) → 2 AgCl (s) + Ca(NO3)2 (aq)…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.600 M Cd(NO₃)₂ reacts with 26.0 mL of…

A: Moles = Molarity x Volume in L For Cd(NO₃)₂, Molarity=0.600 M  Volume=20.5 mL= 0.0205 L Moles =0.600…

Q: What mass of precipitate (in g) is formed when 20.5 mL of 0.700 M Zn(NO₃)₂ reacts with 31.0 mL of…

A: ZnNO32+2 NaOH→ZnOH2 s+2 NaNO3 aqStength of ZnNO32=20.5x0.700 M1000=0.0143Stength of NaOH=310x0.700…

Q: What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M Li₃PO₄ reacts with 44.0 mL of…

A: The balanced reaction given is, => Li₃PO₄(aq) + Cr(NO₃)₃(aq) → CrPO₄(s) + 3 LiNO₃(aq) Given :…

Q: How many moles of precipitate will be formed when 70.2 mL of 0.150 M AgNO₃ is reacted with excess…

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Q: Calculate the mass (in grams) of PbCl2(s) precipitated by mixing 7.16 mL of a 0.187 M Pb(CH3COO)2…

A: We have to calculate the amount of  PbCl2 precipitation

Q: How many moles of precipitate will be formed when 69.3 mL of 0.300 M AgNO₃ is reacted with excess…

A: Given, 69.3 mL of 0.300 M AgNO₃

Q: How many moles of precipitate will be formed when 200.0 mL of 0.400 M NaI is reacted with excess…

A:

Q: How many grams of Ag₂CO3 will precipitate when excess K₂CO3 solution is added to 65.0 mL of 0.746 M…

A:

Q: Generally, only the carbonates of the Group 1 elements and the ammonium ion are soluble in water;…

A: Calcium chloride  reacts with sodium carbonate to get calcium carbonate. Molarity = moles/volume of…

Q: How many moles of precipitate will be formed when 112.0 mL of 0.350 M NaCl is reacted with excess…

A: Given reaction:  2 NaCl (aq) + Pb(NO₃)₂ (aq) → PbCl₂ (s) + 2 NaNO₃ (aq) volume of 0.350 M NaCl…

Q: What quantity in moles of precipitate will be formed when 45.6 mL of 0.550 M AgNO3 is reacted with…

A:

Q: How many moles of precipitate will be formed when 100 mL of 2.00 M NaBr is reacted with 70.0 mL of…

A: The mole of precipitate will be formed has to be determined

Q: How many moles of precipitate will be formed when 74.2 mL of 0.150 M AgNO₃ is reacted with excess…

A:

Q: How many moles of precipitate will be formed when 108.5 mL of 0.200 M NaBr is reacted with excess…

A: Given,Volume of NaBr = 108.5 mL = 0.1085 L       (1 mL =0.001 L)Molarity of NaBr = 0.200 M = 0.2…

Q: Concentration of calcium in a sample may be determined by precipitation using the chromate ion, Cro…

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Q: If 28.0 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: In the reaction ; 2 NaOH(aq) + Ni(NO₃)₂(aq) → Ni(OH)₂ (s) + 2 NaNO₃ (aq) So, we can conclude that 2…

Q: What is the mass in grams of precipitate formed when 86 mL of 0.50 M FeCl3 reacts with excess AgNO3…

A:

Q: How many moles of precipitate will be formed when 69.3 mL of 0.350 M AgNO₃ is reacted with excess…

A: Given the chemical reaction as follows,2 AgNO3(aq) + MgI2(aq) → 2 AgI(s) + Mg(NO3)2(aq)we are asked…

Q: What mass of precipitate (in g) is formed when 80.0 mL of 0.500 M AlCl₃ reacts with excess AgNO₃ in…

A:

Q: How many grams of cobalt(II) chloride are needed to react completely with 30.7 mL of 0.324 M KOH…

A: this is a type of double displacement reaction in which ions of both the salts are getting…

Q: If 32.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: The reaction considered is, 2 NaOH(aq)+Ni(NO3)2(aq)→Ni(OH)2 (s)+ 2 NaNO3(aq)

Q: If 16.5 g of NaOH is added to 0.550 L of 1.00 M Ni(NO₃)₂, how many grams of Ni(OH)₂ will be formed…

A: The balanced reaction given is  2 NaOH(aq) + Ni(NO₃)₂(aq) → Ni(OH)₂ (s) + 2 NaNO₃ (aq) Given : Mass…

Q: How many moles of precipitate will be formed when 85.7 mL of 0.150 M AgNO₃ is reacted with excess…

A:

Q: What quantity in moles of precipitate will be formed when 100.0 mL of 2.00 M NaI is reacted with…

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Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.