What product is formed whenRa-226 undergoes alpha decayThorium-230 undergoes alpha decayC-14 undergoes beta decayThprium-234 undergoes beta decayAs a result of beta decay, bismuth-210 was formed. What was the original radioisotope that decayed to Bi-210?

Since you have posted the question with multiple questions, we will solve the first question for you. To get the remaining question solved please repost the question and mention the question to be solved. Radioactive decay refers to the breakdown of an unstable nucleus to a stable nucleus with the release of high energy particles. Isotopes are those elements which have same atomic number but different mass numbers. There are many isotopes of a lanthanide or actinide which are radioactive.The type of radioactive decay in which high energy alpha particles are released is known as alpha decay. In this decay, the mass number of an element decreases by four and atomic number decreases by two. It is represented by He24. The type of radioactive decay in which high energy beta particles are released is known as beta-decay. They can carry charges of +1 and -1. It is represented by β+and β-particles. 1. In the alpha decay of Ra-226, the mass number decreases by four and atomic number decreases by two to obtain Radon. Write the reaction of decay of Ra-226. Ra88226→Rn86222+He24 2. In the alpha decay of Th-230, the mass number decreases by four and atomic number decreases by two to obtain the nucleus Ra. Write the reaction of decay of Th-230. Th90230→Ra88226+He24 3. In the beta decay of C-14, the mass number remains same and the atomic number increases by one. Write the reaction of beta decay of C-14. C614→N714+e-10 4. In the beta decay of Th-234, the mass number remains same and the atomic number increases by one. Write the reaction of beta decay of Th-234. Th90234→Pa91234+e-10