3.What percentage of the population live in their state of birth? According to theU.S. Census Bureau's American Community Survey, the figure ranges from 25% inNevada to 78.7% in Louisiana. The average percentage across all states and theDistrict of Columbia is 57.7%. In the sample of 180 Virginia residents, 89 are born inVirginia.a. Develop a point estimate and a 95% confidence interval for the proportion ofstay-at-home residents in Virginia.b. Formulate hypotheses that can be used to determine whether the percentage ofstay-at-home residents in Virginia is lower than the overall average of 57.7%c. Compute the value of the test statistic and give the appropriate conclusion usingrejection region approach at a = .05.d. What is the p-value? What is your conclusion based on the p-value?

The average percentage across all states and the district of Columbia is 57.7%.Sample size Number of…

Answered: What percentage of the population live…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A congressperson wants to come up with a single value to describe the prices of homes in their district. However, their district consists of a few homes that are extremely expensive compared to the others. Which descriptive statistic should they use? a. Range b. Mode c. Median d. Mean
In a survey of 3213 adults aged 57 through 85 years, it was found that 83.9% of them used at least one prescription medication. Complete parts (a) through (c) below. a. how many of the 3213 subjects used at least one prescription medication? b. construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. c. what do the results tell us about the proportion of college students who use at least one prescription medication?
Use the data attached: 1. In two to three sentences, explain what a confidence interval means(in general), as if you were talking to someone who has not taken statistics. 2. In one to two sentences, explain what this confidence interval means for this particular study.
A survey of several 11 to 12 year olds recorded the following amounts spent on a trip to the mall: $19.55,$25.44,$25.80,$14.87,$11.83,$19.89 Construct the 80% confidence interval for the average amount spent by 11 to 12 year olds on a trip to the mall. Assume the population is approximately normal. Step 1 of 4 : Calculate the sample mean for the given sample data. Round your answer to two decimal places.
Given the following: Sample Mean = 84.3 Population Variance = 144 Sample size = 35 a. Calculate a 90% confidence interval for the mean. Interpret this interval. b. Calculate a 99% confidence interval for the mean. c. Explain the relationship between Confidence Levels and the resulting intervals.
According to recent data by the American Marketing Association, 76.5%of people in the 18-24 age group used social media in 2017. You want to find out what the social media proportion is among your classmates who are all between 18 and 24 years old. Suppose you obtain a random sample of 229 students and find that 202 students in this sample are active social media users. Complete parts a through c below. a. Construct a 99% confidence interval to estimate the actual proportion of social media users. A 99% confidence interval to estimate the actual proportion has a lower limit of------ and an upper limit of------- (Round to three decimal places as needed.) b. What is the margin of error for this sample? c. Is there evidence that this proportion matches that of the overall population based on the sample?
could you please answer with paper and pen?
Use the sample data and confidence level given below to complete parts (a) through (d). A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n= 1004 and x = 575 who said "yes." Use a 90% confidence level. E Click the icon to view a table of z scores. .... a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.)
The cities with the highest life expectancy are Nowhereville: 84.6 years; Somewhereopolis: 79.8 years; Kinch City: 79.8 years; Tortuga: 84.6 years; Euler Town: 78.5 years; Godelville: 84.6 years; Sirap: 90.1 years. Find the mean, the median, and the mode. ..... Find the mean. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. A. The mean life expectancy is years. (Round to the nearest tenth as needed.) B. The mean does not exist. Find the median. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The median life expectancy is years. (Round to the nearest tenth as needed.) B. The median does not exist. Find the mode. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. The mode life expectancy is years. (Round to the nearest tenth as needed.) O B. The mode does not exist.
A survey of 41 students in grades 4 through 12 found 63% have classroom Wi-Fi access. Find the 99% confidence interval of the population proportion. .
The U.S. National Center for Health Statistics complies birth statistics and publishes the results in vital statistics of the United States. The Center has historically believed that the mean of all newborns in the U.S. has been no less than 6.95 pounds. A sample of babies is selected so that the center can revise its belief. The following birth weights, in pounds are recorded: 7.4, 6.0, 8.6, 4.5, 2.0, 7.9, 4.0, 2.6, 5.9, 7.3, 7.3, 7.0, 6.3, 8.1, 7.1, 7.3, 6.6, 5.2, 9.8, 8.0, 10.9, 6.5, 3.8, 5.0, 8.0 a). At 5% level of significance, do these data provide sufficient evidence to refute the Center’s belief? Your conclusion must be in terms of the P-Value as well as setting up a Rejection Region. You must show all necessary work. b). Which statistical distribution should be applied in this situation and why? Explain carefully.

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