What molar ratio of salt to acid would be required to prepare a buffer solution with a pH of 5.9? The pKa of the acid is 5.7.How many grams of ammonium sulfate ((NH4 )2SO4 )) would you need to add to 425 mL of 0.28 M ammonia (NH3 ) to obtain a buffer solution with a pH of 9.45. Assume that the volume doesn’t change when you add the salt. Ka for the ammonium ion is 5.8 x 10-10 . (be careful with how the reaction for ammonium is written as well as stoichiometry)A 1.00 L volume of buffer is made with concentrations of 0.350 M sodium formate (NaHCOO) and 0.550 M formic acid (HCOOH). (Ka of HCOOH is 1.8 x 10-4 ) a. Calculate the initial pH of this buffer. b. What is the pH after the addition of 0.0050 mol HCl? c. How about after the addition of 0.0050 mol NaOH? [For parts b and c, assume that volume doesn’t change in the addition process and that neutralization proceeds to completion]

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Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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What molar ratio of salt to acid would be required to prepare a buffer solution with a pH of 5.9? The pKa of the acid is 5.7.
How many grams of ammonium sulfate ((NH4 )2SO4 )) would you need to add to 425 mL of 0.28 M ammonia (NH3 ) to obtain a buffer solution with a pH of 9.45. Assume that the volume doesn’t change when you add the salt. Ka for the ammonium ion is 5.8 x 10-10 . (be careful with how the reaction for ammonium is written as well as stoichiometry)
A 1.00 L volume of buffer is made with concentrations of 0.350 M sodium formate (NaHCOO) and 0.550 M formic acid (HCOOH). (Ka of HCOOH is 1.8 x 10-4 ) a. Calculate the initial pH of this buffer. b. What is the pH after the addition of 0.0050 mol HCl? c. How about after the addition of 0.0050 mol NaOH? [For parts b and c, assume that volume doesn’t change in the addition process and that neutralization proceeds to completion]

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