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What mass of solute is required to produce 414.8 mL of a 0.256 Msolution of KBr? g KBr

What mass of solute is required to produce 414.8 mL of a 0.256 Msolution of KBr? g KBr

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Question:** What mass of solute is required to produce 414.8 mL of a 0.256 M solution of KBr? [Blank] g KBr **Explanation:** To find the mass of potassium bromide (KBr) needed, we can use the formula: \[ \text{Mass (g)} = \text{Volume (L)} \times \text{Molarity (M)} \times \text{Molar Mass of KBr (g/mol)} \] 1. **Convert Volume to Liters:** - 414.8 mL = 0.4148 L 2. **Molarity (M):** - 0.256 M 3. **Molar Mass of KBr:** - Potassium (K): approximately 39.1 g/mol - Bromine (Br): approximately 79.9 g/mol - Molar Mass of KBr = 39.1 + 79.9 = 119.0 g/mol 4. **Calculate Mass:** - Mass = 0.4148 L × 0.256 M × 119.0 g/mol - Mass ≈ 12.64 g Therefore, approximately 12.64 grams of KBr is required.
Transcribed Image Text:**Question:** What mass of solute is required to produce 414.8 mL of a 0.256 M solution of KBr? [Blank] g KBr **Explanation:** To find the mass of potassium bromide (KBr) needed, we can use the formula: \[ \text{Mass (g)} = \text{Volume (L)} \times \text{Molarity (M)} \times \text{Molar Mass of KBr (g/mol)} \] 1. **Convert Volume to Liters:** - 414.8 mL = 0.4148 L 2. **Molarity (M):** - 0.256 M 3. **Molar Mass of KBr:** - Potassium (K): approximately 39.1 g/mol - Bromine (Br): approximately 79.9 g/mol - Molar Mass of KBr = 39.1 + 79.9 = 119.0 g/mol 4. **Calculate Mass:** - Mass = 0.4148 L × 0.256 M × 119.0 g/mol - Mass ≈ 12.64 g Therefore, approximately 12.64 grams of KBr is required.
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