What mass of precipitate (in g) is formed when 45.5 mL of 0.300 M K3PO4 reacts with 52.5 mL of 0.200 M Cr(NO3)3 in the following chemical reaction? K3PO4(aq) + Cr(NO3)3(aq) → CrPO4 (s) + 3 KNO3 (aq)

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Chapter1: Chemical Foundations
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**Question 9 of 19**

**Problem Statement:**

What mass of precipitate (in grams) is formed when 45.5 mL of 0.300 M \( K_3PO_4 \) reacts with 52.5 mL of 0.200 M \( Cr(NO_3)_3 \) in the following chemical reaction?

\[ K_3PO_4(aq) + Cr(NO_3)_3(aq) \rightarrow CrPO_4(s) + 3 KNO_3(aq) \]

**Input Interface:**

- A numeric keypad is displayed for entering the answer, with buttons numbered from 1 to 9, 0, and options to clear the input or delete the last entry.
- The input is expected in grams (`g`).

There are no graphs or diagrams accompanying the text, only the problem statement and the interactive input interface.
Transcribed Image Text:**Question 9 of 19** **Problem Statement:** What mass of precipitate (in grams) is formed when 45.5 mL of 0.300 M \( K_3PO_4 \) reacts with 52.5 mL of 0.200 M \( Cr(NO_3)_3 \) in the following chemical reaction? \[ K_3PO_4(aq) + Cr(NO_3)_3(aq) \rightarrow CrPO_4(s) + 3 KNO_3(aq) \] **Input Interface:** - A numeric keypad is displayed for entering the answer, with buttons numbered from 1 to 9, 0, and options to clear the input or delete the last entry. - The input is expected in grams (`g`). There are no graphs or diagrams accompanying the text, only the problem statement and the interactive input interface.
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