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What mass of PbCl, can form from 0.235L of 0.110 M KCI solution if there is plenty of Pb(NO), present? Molar mass of PbCl, is 278.1 g/mol Balanced reaction: 2KCI(ag) + Pb(NOhlaq) – PbCl,(s) + 2KNO,(aq) 0719 g O3.59 E O5.94 g O180g

What mass of PbCl, can form from 0.235L of 0.110 M KCI solution if there is plenty of Pb(NO), present? Molar mass of PbCl, is 278.1 g/mol Balanced reaction: 2KCI(ag) + Pb(NOhlaq) – PbCl,(s) + 2KNO,(aq) 0719 g O3.59 E O5.94 g O180g

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Problem Statement:** What mass of PbCl₂ can form from 0.235 L of 0.110 M KCl solution if there is plenty of Pb(NO₃)₂ present? The molar mass of PbCl₂ is 278.1 g/mol. **Balanced Reaction:** 2KCl(aq) + Pb(NO₃)₂(aq) → PbCl₂(s) + 2KNO₃(aq) **Options:** - 7.19 g - 3.59 g - 5.94 g - 1.80 g - 1.30 g
Transcribed Image Text:**Problem Statement:** What mass of PbCl₂ can form from 0.235 L of 0.110 M KCl solution if there is plenty of Pb(NO₃)₂ present? The molar mass of PbCl₂ is 278.1 g/mol. **Balanced Reaction:** 2KCl(aq) + Pb(NO₃)₂(aq) → PbCl₂(s) + 2KNO₃(aq) **Options:** - 7.19 g - 3.59 g - 5.94 g - 1.80 g - 1.30 g
Expert Solution
Step 1

Limiting reactant is the one that is present is less amount than required for the completion of the reaction. 

It is given that there is plenty of Pb(NO3)2. So KCl is the limiting reagent and decides the amount of product formed.

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