What mass of Na2CO3, in grams, is required for complete reaction with 59.9 mL of 0.125 M HNO3 ? Na2CO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO₂(g) + H₂O(l) g Na2CO3 Mass=
What mass of Na2CO3, in grams, is required for complete reaction with 59.9 mL of 0.125 M HNO3 ? Na2CO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO₂(g) + H₂O(l) g Na2CO3 Mass=
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
What mass of \( \text{Na}_2\text{CO}_3 \), in grams, is required for complete reaction with 59.9 mL of 0.125 M \( \text{HNO}_3 \)?
**Chemical Reaction:**
\[ \text{Na}_2\text{CO}_3(\text{aq}) + 2 \text{HNO}_3(\text{aq}) \rightarrow 2 \text{NaNO}_3(\text{aq}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\ell) \]
**Calculation:**
Mass \( = \underline{\hspace{2cm}} \text{g Na}_2\text{CO}_3 \)
---
**Explanation:**
To solve this problem, follow these steps:
1. **Calculate the moles of \( \text{HNO}_3 \) used:**
- Use the concentration (Molarity) and volume information provided.
\[
\text{Moles of } \text{HNO}_3 = \text{Molarity} \times \text{Volume (in liters)}
\]
2. **Determine the stoichiometric relationship:**
- Based on the balanced chemical equation, 1 mole of \( \text{Na}_2\text{CO}_3 \) reacts with 2 moles of \( \text{HNO}_3 \).
- Use the mole ratio to calculate the moles of \( \text{Na}_2\text{CO}_3 \) needed.
3. **Calculate the mass of \( \text{Na}_2\text{CO}_3 \):**
- Use the molar mass of \( \text{Na}_2\text{CO}_3 \) to convert moles to grams.
\[
\text{Mass of } \text{Na}_2\text{CO}_3 = \text{Moles of } \text{Na}_2\text{CO}_3 \times \text{Molar Mass of } \text{Na}_2\text{CO}_3
\]
Place the computed mass value in the provided space to complete the statement.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7a354f1c-cdfd-41e5-a863-9a86a504af1c%2Fc6af2232-c78e-41d8-aa0a-6b99c8d0f03a%2Fqfxhlse_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
What mass of \( \text{Na}_2\text{CO}_3 \), in grams, is required for complete reaction with 59.9 mL of 0.125 M \( \text{HNO}_3 \)?
**Chemical Reaction:**
\[ \text{Na}_2\text{CO}_3(\text{aq}) + 2 \text{HNO}_3(\text{aq}) \rightarrow 2 \text{NaNO}_3(\text{aq}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\ell) \]
**Calculation:**
Mass \( = \underline{\hspace{2cm}} \text{g Na}_2\text{CO}_3 \)
---
**Explanation:**
To solve this problem, follow these steps:
1. **Calculate the moles of \( \text{HNO}_3 \) used:**
- Use the concentration (Molarity) and volume information provided.
\[
\text{Moles of } \text{HNO}_3 = \text{Molarity} \times \text{Volume (in liters)}
\]
2. **Determine the stoichiometric relationship:**
- Based on the balanced chemical equation, 1 mole of \( \text{Na}_2\text{CO}_3 \) reacts with 2 moles of \( \text{HNO}_3 \).
- Use the mole ratio to calculate the moles of \( \text{Na}_2\text{CO}_3 \) needed.
3. **Calculate the mass of \( \text{Na}_2\text{CO}_3 \):**
- Use the molar mass of \( \text{Na}_2\text{CO}_3 \) to convert moles to grams.
\[
\text{Mass of } \text{Na}_2\text{CO}_3 = \text{Moles of } \text{Na}_2\text{CO}_3 \times \text{Molar Mass of } \text{Na}_2\text{CO}_3
\]
Place the computed mass value in the provided space to complete the statement.
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