What mass of Na2CO3, in grams, is required for complete reaction with 59.9 mL of 0.125 M HNO3 ? Na2CO3(aq) + 2 HNO3(aq) → 2 NaNO3(aq) + CO₂(g) + H₂O(l) g Na2CO3 Mass=

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**Problem Statement:**

What mass of \( \text{Na}_2\text{CO}_3 \), in grams, is required for complete reaction with 59.9 mL of 0.125 M \( \text{HNO}_3 \)?

**Chemical Reaction:**

\[ \text{Na}_2\text{CO}_3(\text{aq}) + 2 \text{HNO}_3(\text{aq}) \rightarrow 2 \text{NaNO}_3(\text{aq}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\ell) \]

**Calculation:**

Mass \( = \underline{\hspace{2cm}} \text{g Na}_2\text{CO}_3 \)

---

**Explanation:**

To solve this problem, follow these steps:

1. **Calculate the moles of \( \text{HNO}_3 \) used:**
   - Use the concentration (Molarity) and volume information provided.
   
   \[
   \text{Moles of } \text{HNO}_3 = \text{Molarity} \times \text{Volume (in liters)}
   \]

2. **Determine the stoichiometric relationship:**
   - Based on the balanced chemical equation, 1 mole of \( \text{Na}_2\text{CO}_3 \) reacts with 2 moles of \( \text{HNO}_3 \).
   - Use the mole ratio to calculate the moles of \( \text{Na}_2\text{CO}_3 \) needed.

3. **Calculate the mass of \( \text{Na}_2\text{CO}_3 \):**
   - Use the molar mass of \( \text{Na}_2\text{CO}_3 \) to convert moles to grams.
   
   \[
   \text{Mass of } \text{Na}_2\text{CO}_3 = \text{Moles of } \text{Na}_2\text{CO}_3 \times \text{Molar Mass of } \text{Na}_2\text{CO}_3
   \]

Place the computed mass value in the provided space to complete the statement.
Transcribed Image Text:**Problem Statement:** What mass of \( \text{Na}_2\text{CO}_3 \), in grams, is required for complete reaction with 59.9 mL of 0.125 M \( \text{HNO}_3 \)? **Chemical Reaction:** \[ \text{Na}_2\text{CO}_3(\text{aq}) + 2 \text{HNO}_3(\text{aq}) \rightarrow 2 \text{NaNO}_3(\text{aq}) + \text{CO}_2(\text{g}) + \text{H}_2\text{O}(\ell) \] **Calculation:** Mass \( = \underline{\hspace{2cm}} \text{g Na}_2\text{CO}_3 \) --- **Explanation:** To solve this problem, follow these steps: 1. **Calculate the moles of \( \text{HNO}_3 \) used:** - Use the concentration (Molarity) and volume information provided. \[ \text{Moles of } \text{HNO}_3 = \text{Molarity} \times \text{Volume (in liters)} \] 2. **Determine the stoichiometric relationship:** - Based on the balanced chemical equation, 1 mole of \( \text{Na}_2\text{CO}_3 \) reacts with 2 moles of \( \text{HNO}_3 \). - Use the mole ratio to calculate the moles of \( \text{Na}_2\text{CO}_3 \) needed. 3. **Calculate the mass of \( \text{Na}_2\text{CO}_3 \):** - Use the molar mass of \( \text{Na}_2\text{CO}_3 \) to convert moles to grams. \[ \text{Mass of } \text{Na}_2\text{CO}_3 = \text{Moles of } \text{Na}_2\text{CO}_3 \times \text{Molar Mass of } \text{Na}_2\text{CO}_3 \] Place the computed mass value in the provided space to complete the statement.
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