**Question:**What mass of aluminum oxide (101.96 g/mol) is produced by the complete reaction of 150. g of aluminum (26.98 g/mol)? Assume unlimited oxygen from air.**Chemical Reaction:**\[ 4 \text{Al}_{(s)} + 3 \text{O}_{2(g)} \rightarrow 2 \text{Al}_2\text{O}_{3(s)} \]**Answer Choices:**- ○ 375 g- ○ 283 g- ○ 1.13 mg- ○ 79.4 g**Explanation:**The chemical equation shows that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. Given the molar masses, calculate the mass of aluminum oxide produced from 150 grams of aluminum. Use stoichiometry to determine which answer is correct based on the balanced equation and the molar masses provided.

Given data, Mass of aluminium (Al) = 150 g Molar mass of Al = 26.98 g/mol Molar mass of Al2O3 =…

What mass of aluminum oxide (101.96 g/mol) is produced by complete reaction of 150. g aluminum (26.98 g/mol)? Assume unlimited oxygen from air. --> 2 Al2O3(s) 4 Alts) + 3 O2(g) 375 g 283 g O 1.13 mg O 79.4 g

What mass of aluminum oxide (101.96 g/mol) is produced by complete reaction of 150. g aluminum (26.98 g/mol)? Assume unlimited oxygen from air. --> 2 Al2O3(s) 4 Alts) + 3 O2(g) 375 g 283 g O 1.13 mg O 79.4 g

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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