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What is T₂(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x-8)+3(x-4)² +3(x-12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x-3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³

What is T₂(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x-8)+3(x-4)² +3(x-12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x-3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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What is T3(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x−8)+3(x−4)² +3(x−12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x − 3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³
Transcribed Image Text:What is T3(x) centered at a = 3 for a function f(x) such that f(3) = 9, f '(3) = 8, f "(3) = 4, and f "(3) = 12? A.T₂(x)=9+3(x−8)+3(x−4)² +3(x−12)³ B.T3(x)=9+8(x-3)+4(x-3)² C.T3(x)=9+8(x-3)+2(x-3)² + 2(x − 3)³ D.T₂(x)=9+8(x-3)+4(x-3)² +12(x-3)³
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