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A function f(x) has an inflection point at (2,-2). Which of the following could NOT have been the result of the test which confirmed this? Select one alternative: f" (2) = 0, f"(0)=1, and f"(3) = -4 f" (2) = 0, f" (0) = -4, and f"(3) = 7 f" (2) = 0, ƒ" (0) = −3, and ƒ"(3) = 1 f" (2) = 0, f"(0) = 12, and f"(3) = 7

A function f(x) has an inflection point at (2,-2). Which of the following could NOT have been the result of the test which confirmed this? Select one alternative: f" (2) = 0, f"(0)=1, and f"(3) = -4 f" (2) = 0, f" (0) = -4, and f"(3) = 7 f" (2) = 0, ƒ" (0) = −3, and ƒ"(3) = 1 f" (2) = 0, f"(0) = 12, and f"(3) = 7

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A function f(x) has an inflection point at (2,-2). Which of the following could NOT have been the result of the test which confirmed this? Select one alternative: f" (2) = 0, f" (0)=1, and f"(3) = −4 f" (2) = 0, f" (0) = -4, and f"(3) = 7 f" (2) = 0, f" (0) = -3, and f"(3) = 1 f" (2) = 0, f" (0) = 12, and f"(3) = 7
Transcribed Image Text:A function f(x) has an inflection point at (2,-2). Which of the following could NOT have been the result of the test which confirmed this? Select one alternative: f" (2) = 0, f" (0)=1, and f"(3) = −4 f" (2) = 0, f" (0) = -4, and f"(3) = 7 f" (2) = 0, f" (0) = -3, and f"(3) = 1 f" (2) = 0, f" (0) = 12, and f"(3) = 7
Expert Solution
Step 1

We know that point of inflection can occur where the second derivative is 0.

It is the point at which concavity of the function changes.

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