What is the y' of y=tan (6x-5)? a. y' = 6 csc2 (6x-5) b. y' = 6 cot (6x-5) c. y = 6 sec2 (6x-5) d. y = tan (6)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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What is the y' ofy=tan (6x-5)?
а. у 36 csc? (6x-5)
b. y' = 6 cot (6x-5)
с. у36 sec? (6х-5)
d. y = tan (6)
What is the second derivative of y = 6x4 – 3x3 + x2 – 5
a. y" = 24x3 – 9x? + 2x
b. y" = 144
с. у"%3D72х2- 18х +2
d. y'3 144х - 18
What is the derivative of f(x) = e&x + 3?
a. f(x) = 8e
b. f(x) = e8
f(x) = 8e&x*3
d. f(x) = 3e8x
%3D
C.
What is the third derivative of y = 2x5 – 2x4 + 5x3 + 6?
y" = 120x2 – 48x + 30
b. y" 3 10х4- 8х3 + 15х2
c. y" = 2x4 – 2x³ + 5x2
d. y" = 40x3 – 24x2 + 30x
%3D
a.
What is the derivative with respect to x of f(x) = (5 – x²)²?
а. 4x3 -20х
b. 2(5 -х?)
с. (5- х) (5-х)
10 – 2x2
С.
d.
Transcribed Image Text:What is the y' ofy=tan (6x-5)? а. у 36 csc? (6x-5) b. y' = 6 cot (6x-5) с. у36 sec? (6х-5) d. y = tan (6) What is the second derivative of y = 6x4 – 3x3 + x2 – 5 a. y" = 24x3 – 9x? + 2x b. y" = 144 с. у"%3D72х2- 18х +2 d. y'3 144х - 18 What is the derivative of f(x) = e&x + 3? a. f(x) = 8e b. f(x) = e8 f(x) = 8e&x*3 d. f(x) = 3e8x %3D C. What is the third derivative of y = 2x5 – 2x4 + 5x3 + 6? y" = 120x2 – 48x + 30 b. y" 3 10х4- 8х3 + 15х2 c. y" = 2x4 – 2x³ + 5x2 d. y" = 40x3 – 24x2 + 30x %3D a. What is the derivative with respect to x of f(x) = (5 – x²)²? а. 4x3 -20х b. 2(5 -х?) с. (5- х) (5-х) 10 – 2x2 С. d.
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