What is the VERTICAL component of the electric field at the point in the picture? Denote up as positive, down as negative. 2.0 cm 10 nC + 4.0 cm 5.0 nC + O +2.9e4 N/C O-1.2e4 N/C O -3.7e4 N/C O-2.5e4 N/C O +4.6e4 N/C -5.0 nC
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Q: Determine the electric field at points 1 and 2. -2.0 nC 1.0 cm 1.0 cm 1.0 cm 2
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- Find the electric field, at the point shown in the figure, in magnitude and direction. -5.0 nC 10 nC 4.0 cm 2.0 cm + + 10 nCHow to solve this question1. In the following problems, you don't need to understand the physics to complete the questions. Focus on the equations. (a) The force of gravity, F, between two masses, m and M, separated by a distance r, is given by GmM where G is a constant. Write an equation of r in terms of other variables in the equation F= for F: r= GmM F (b) The electric force between two charges q=3-10-6 units and Q=-4·10¯6 units separated by a distance, d = 3.10-4 units, is given by F= kqQ d² I where k=9. 10⁹ units. Without using a calculator, calculate the F. F= -12x10 -5 Ⓡ√
- A pyramid has a square base with an area of 7.50 m² and a height of 3.5 m. Its walls are four isosceles triangles. The pyramid is in a uniform electric field of 950 N/C pointing downward (see figure below). What is the electric flux through all four walls combined? N-m²/c B hAssume that R₁ > R₂ and rank the segments according to the magnitude of the average electric field in them, greatest first. F R₁ R₂ mm O a. b=d> a = c = e O b. a> b> c>d>e O C. O d. b> d > a = c = e O e. a = b = c d = e a = c = e = e> b = d d eThe figure shows an electric dipole. What is the magnitude of the dipole's electric field at point P? Assume that q = 1.34 x 10-6 c, d = 8.65 x 10-6 m, and r = 7.81 cm. +q L. P Number MI d/2 F d/2 Units <
- For this figure, what is the magnitude of the electric field at point A? +5.0 nC 4.0 m A -10.0 nC 3.0 mPlease solve asap and explain in detail how you reached the solutionGiven that q1 = 6.20 nC, q2 = -1.8 nC, a = 9.80 cm and b = 2.00 cm. What is the magntude of the electric field at point p? 3.47×104 N/C 4.09×104 N/C 1.73×104 N/C 4.63×104 N/C
- A point charge gives rise to an electric field with magnitude 4 N/C at a distance of 8 m. If the distance is increased to 16 m, then what will be the new magnitude of the electric field? N/CDetermine the magnitude and direction of the electric field at points 1 and 2 in the figure below. 75 V 50 V 1 T 1 1 1 I 1 1 1 25 V OV 1 V I 1 1 I 1 cm 1 cmWhich expression gives the correct electric field magnitude at point P for the geometry shown in the figure? 1 2g 4περ r 1 E = b- 2 E = v2; 2q 4T€0 r2 1 r , 4 50% || b- 2 1 E = /2; 4T€0 r2 CORRECT V2 _1 2 4T€0 E = 50% P.