Two point charges each have a value of 3.0 C and are separated by a distance of 4.0 m. What is the electric field at a point midway between the two charges? O zero O 9.0 x 107 N/C O 18 x 107 N/C O 4.5 x 107 N/C
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Q: In the figure the four particles are fixed in place and have charges 91 92 = 3e, 93 = 3e, and 94 =…
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- In the figure the four particles are fixed in place and have charges q₁ = 92 = 4e, 93 = 2e, and 94 = -8e. Distance d = 5.96 µm. What is the magnitude of the net electric field at point P due to the particles? Number i Stop A Units His de lu 91 d P > 93 92 94 AWhat is the magnitude of the y component of the net electric field at the point A? The two charges and point A are each a distance of W from the origin. +y +Q В x+ |(0,0) 2W 2 W 2 W 2 O 4/ ZkQ w 2 O The y component of the net E field at A is zero. 2kQ W 2 O OConsider the electric dipole shown in the figure. (a) Show that the electric field at a distant point on the x-axis is Ex = 4kqa/x3 (b) Where do you think you might find the expression of electric field from a dipole useful?
- A particle with a charge of q₁ = -4.0 C is placed 5.0 m away from another charged particle q2 = +9.0 C. Find the magnitude and direction of electric field at point A which is shown in the figure. k = 9.00 x 109 Nm² C2 9₁ = -4C 2 m A 5 m 45 x 10⁹ N/C (to the left) 18 x 10⁹ N/C (to the right) 18 x 10⁹ N/C (to the left) 45 x 10⁹ N/C (to the left) I 3 m 92 = +9C Left RightA charge of +2 C is at the origin. When charge Q is placed at 2 m along the positive x axis, the electric field at 2 m along the negative x axis becomes zero. What is the value of Q?Two point charges lie along the y-axis. A charge of q1 = -7.5 ?C is at y = 6.0 m, and a charge of q2 = -7.5 ?C is at y = -4.0 m. Locate the point (other than infinity) at which the total electric field is zero.
- An electron is placed in a uniform electric field of 28x10^-9 N/C directed north created by two horizontal parallel plates that are 135x10^-15 m apart. The electron accelerates from rest, starting at the negative plate. What is the net force and acceleration acting on the electron? How long did it take the electron to get from one side of the plate to the other?please answer this questionA small plastic bead has a mass of 3.68 g and a charge of -16.6 µC. It levitates, motionless, when placed in a uniform electric field perpendicular to the ground. What is the magnitude of the electric field (in N/C)? N/C What is the direction of the electric field? O upward O downward O east O west
- 0 5 +9 10 x (cm) -2q +q Point charges are located at 3.00, 8.00, and 11.0 cm along the x-axis. What is the total electric field at the origin?Three charges are placed along the x-axis: q1 = 3.00 µC at X1 = -20.0 cm, q2 = -5.00 µC at x2 = 10.0 cm, and q3 = 6.00 µC at x3 = 25.00 cm. Determine the magnitude of the electric field at the origin. O 4 69x106 N/C O 2 96x106 N/C O 6 04x106 N/C O 4.31x106 N/CThree charges are at the corners of an equilateral triangle, as shown in the figure below. Calculate the electric field at a point midway between the two charges on the x-axis. (Let q, = 9.00 uC, q2 = 4.50 uC, and q3 = -3.50 uC.) 0.500 m 60.0° |N/C below the +x-axis magnitude direction