What is the value of the of the frictional force based on the force applied? Assume the box starts stationary. 1. Ff 100 N 1 v FA = 623 N 2. Ff = 312 N FA = 699 N %3D 3. Ff = 353 N FA=437 N %3D 4. Ff = 437 N FA = 100 N %3D 5. F= 588 N FA = 588 N %3D 6. Ff= 623 N FA=312 N %3D 7. Ff= 699 N <> <> <. <>

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What is the value of the of the frictional force based on the force applied? Assume the box starts stationary.

**Educational Content on Frictional Force**

**Question:**
What is the value of the frictional force based on the force applied? Assume the box starts stationary.

**Options for Applied Force (\(F_A\)):**
1. \(F_A = 623 \, \text{N}\)
2. \(F_A = 699 \, \text{N}\)
3. \(F_A = 437 \, \text{N}\)
4. \(F_A = 100 \, \text{N}\)
5. \(F_A = 588 \, \text{N}\)
6. \(F_A = 312 \, \text{N}\)

**Options for Frictional Force (\(F_f\)):**
1. \(F_f = 100 \, \text{N}\)
2. \(F_f = 312 \, \text{N}\)
3. \(F_f = 353 \, \text{N}\)
4. \(F_f = 437 \, \text{N}\)
5. \(F_f = 588 \, \text{N}\)
6. \(F_f = 623 \, \text{N}\)
7. \(F_f = 699 \, \text{N}\)

**Explanation of Concepts:**
- When a box is stationary, the frictional force (\(F_f\)) is equal to or less than the applied force (\(F_A\)) up to a maximum limit.
- The box moves when the applied force exceeds the maximum static friction.
- Analyze each applied force to determine the corresponding frictional force, considering that static friction prevents motion until exceeded.
Transcribed Image Text:**Educational Content on Frictional Force** **Question:** What is the value of the frictional force based on the force applied? Assume the box starts stationary. **Options for Applied Force (\(F_A\)):** 1. \(F_A = 623 \, \text{N}\) 2. \(F_A = 699 \, \text{N}\) 3. \(F_A = 437 \, \text{N}\) 4. \(F_A = 100 \, \text{N}\) 5. \(F_A = 588 \, \text{N}\) 6. \(F_A = 312 \, \text{N}\) **Options for Frictional Force (\(F_f\)):** 1. \(F_f = 100 \, \text{N}\) 2. \(F_f = 312 \, \text{N}\) 3. \(F_f = 353 \, \text{N}\) 4. \(F_f = 437 \, \text{N}\) 5. \(F_f = 588 \, \text{N}\) 6. \(F_f = 623 \, \text{N}\) 7. \(F_f = 699 \, \text{N}\) **Explanation of Concepts:** - When a box is stationary, the frictional force (\(F_f\)) is equal to or less than the applied force (\(F_A\)) up to a maximum limit. - The box moves when the applied force exceeds the maximum static friction. - Analyze each applied force to determine the corresponding frictional force, considering that static friction prevents motion until exceeded.
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