What is the two-sample test formula? Step 1: Testing the claim that the difference in means is equal for men and women. The two-sample t-interval test would be appropriate to compare which is the confidence interval test. Step 2: Let p1 state the mean for the times of handwashing for men. Let p2 state the mean for the times of handwashing times for women. The difference in mean times of men and women are equal. The hypothesis is, Null hypothesis: (Claim) H0: p1 = p2 Alternative hypothesis: Ha: p1 ≠ p2 Step 3: Two tail test ( p-value = twice the smaller of the proceeding left-tailed and right-tailed values)
What is the two-sample test formula? Step 1: Testing the claim that the difference in means is equal for men and women. The two-sample t-interval test would be appropriate to compare which is the confidence interval test. Step 2: Let p1 state the mean for the times of handwashing for men. Let p2 state the mean for the times of handwashing times for women. The difference in mean times of men and women are equal. The hypothesis is, Null hypothesis: (Claim) H0: p1 = p2 Alternative hypothesis: Ha: p1 ≠ p2 Step 3: Two tail test ( p-value = twice the smaller of the proceeding left-tailed and right-tailed values)
MATLAB: An Introduction with Applications
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ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
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Question
What is the two-sample test formula?
Step 1: Testing the claim that the difference in means is equal for men and women. The two-sample t-interval test would be appropriate to compare which is the confidence interval test.
Step 2: Let p1 state the
Null hypothesis: (Claim)
H0: p1 = p2
Alternative hypothesis:
Ha: p1 ≠ p2
Step 3: Two tail test ( p-value = twice the smaller of the proceeding left-tailed and right-tailed values)
![WOMEN MΕAΝ (S)
MEN MEAN (S)
14.34
10.33
SECONDS
SECONDS
FEMALE Histogram
MALE Histogram
Mean
14.34
Mean
10.33
Standard Deviation (s)
10.82
Standard Deviation (s)
10.34
Variance
115.12
Variance
105.07
Median
14.95
Median
8.6
Mode
Mode
Skewness
0.72
Skewness
0.97
Kurtosis
0.36
Kurtosis
0.77
Lowest Score
0.00
Lowest Score
0.00
Highest Score
Distribution Range
Highest Score
Distribution Range
47.15
45.31
47.15
45.31
Total Number of Scores
59.00
Total Number of Scores
59.00
Number of Distinct Scores
52.00
Number of Distinct Scores
41.00
Lowest Class Value
0.00
Lowest Class Value
0.00
Highest Class Value
53.99
Highest Class Value
47.99
Number of Classes
6.00
Number of Classes
6.00
Class Range
9.00
Class Range
8.00](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8fa81bc8-af1f-42ce-b4f9-1a3d9b9327df%2F291c8af0-e5b2-4037-9e29-d85d92330698%2Fly4e041_processed.png&w=3840&q=75)
Transcribed Image Text:WOMEN MΕAΝ (S)
MEN MEAN (S)
14.34
10.33
SECONDS
SECONDS
FEMALE Histogram
MALE Histogram
Mean
14.34
Mean
10.33
Standard Deviation (s)
10.82
Standard Deviation (s)
10.34
Variance
115.12
Variance
105.07
Median
14.95
Median
8.6
Mode
Mode
Skewness
0.72
Skewness
0.97
Kurtosis
0.36
Kurtosis
0.77
Lowest Score
0.00
Lowest Score
0.00
Highest Score
Distribution Range
Highest Score
Distribution Range
47.15
45.31
47.15
45.31
Total Number of Scores
59.00
Total Number of Scores
59.00
Number of Distinct Scores
52.00
Number of Distinct Scores
41.00
Lowest Class Value
0.00
Lowest Class Value
0.00
Highest Class Value
53.99
Highest Class Value
47.99
Number of Classes
6.00
Number of Classes
6.00
Class Range
9.00
Class Range
8.00
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
Given
n1 = n2 = 59
x1 = 14.34
x2 = 10.33
s1 = 10.82
s2 = 10.34
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