What is the total mechanical energy for a ground- state electron in H, He+, and Li++ atoms? For which atom is the electron most strongly bound? Why?

Physics for Scientists and Engineers with Modern Physics
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Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter41: Atomic Physics
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On this educational page, we start by examining a fundamental question in atomic physics:

**Question:**
What is the total mechanical energy for a ground-state electron in H, He⁺, and Li⁺⁺ atoms? For which atom is the electron most strongly bound? Why?

**Explanation:**

- **H Atom (Hydrogen):**
  Hydrogen has one electron and one proton. For a ground-state electron in hydrogen, the total mechanical energy, often represented as the energy level of the electron, is calculated using the Bohr model of the atom. The energy \( E_n \) of an electron in the nth orbit of a hydrogen atom is given by:

  \[
  E_n = - \frac{13.6 \text{ eV}}{n^2}
  \]

  For the ground state, \( n=1 \).

  \[
  E_1 = -13.6 \text{ eV}
  \]

- **He⁺ Ion (Helium ion):**
  Helium originally has two protons, but the He⁺ ion means it has one electron removed, leaving just one electron and two protons. The total mechanical energy for a ground-state electron can be calculated similarly but needs to account for the increased nuclear charge (Z=2):

  \[
  E_n = - \frac{13.6 \text{ eV} \cdot Z^2}{n^2}
  \]

  So for Helium ion \( ( \text{He}^+ , Z=2 ) \):

  \[
  E_1 = - 13.6 \text{ eV} \cdot 2^2 = - 54.4 \text{ eV}
  \]

- **Li⁺⁺ Ion (Lithium ion):**
  Lithium originally has three protons, but the \( \text{Li}^{++} \) ion means it has lost two electrons, leaving one electron and three protons. The total mechanical energy for a ground-state electron is:

  \[
  E_n = - \frac{13.6 \text{ eV} \cdot Z^2}{n^2}
  \]

  For the Lithium ion \( ( \text{Li}^{++} , Z=3 ) \):

  \[
  E_1 = - 13.6 \text{ eV} \
Transcribed Image Text:On this educational page, we start by examining a fundamental question in atomic physics: **Question:** What is the total mechanical energy for a ground-state electron in H, He⁺, and Li⁺⁺ atoms? For which atom is the electron most strongly bound? Why? **Explanation:** - **H Atom (Hydrogen):** Hydrogen has one electron and one proton. For a ground-state electron in hydrogen, the total mechanical energy, often represented as the energy level of the electron, is calculated using the Bohr model of the atom. The energy \( E_n \) of an electron in the nth orbit of a hydrogen atom is given by: \[ E_n = - \frac{13.6 \text{ eV}}{n^2} \] For the ground state, \( n=1 \). \[ E_1 = -13.6 \text{ eV} \] - **He⁺ Ion (Helium ion):** Helium originally has two protons, but the He⁺ ion means it has one electron removed, leaving just one electron and two protons. The total mechanical energy for a ground-state electron can be calculated similarly but needs to account for the increased nuclear charge (Z=2): \[ E_n = - \frac{13.6 \text{ eV} \cdot Z^2}{n^2} \] So for Helium ion \( ( \text{He}^+ , Z=2 ) \): \[ E_1 = - 13.6 \text{ eV} \cdot 2^2 = - 54.4 \text{ eV} \] - **Li⁺⁺ Ion (Lithium ion):** Lithium originally has three protons, but the \( \text{Li}^{++} \) ion means it has lost two electrons, leaving one electron and three protons. The total mechanical energy for a ground-state electron is: \[ E_n = - \frac{13.6 \text{ eV} \cdot Z^2}{n^2} \] For the Lithium ion \( ( \text{Li}^{++} , Z=3 ) \): \[ E_1 = - 13.6 \text{ eV} \
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