What is the total irradiance of a blackbody at the temperature of 200K. Provide you answer in units of W/m2.
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A: Given :- power emitted by a blackbody is proportional to T^4 T1 = 3000 K T2 = 6000K
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Q: Calculate the temperature of a blackbody that peaks at a frequency of 7.5·108 MHz.
A: Given Fmax = 7.5 x 108 MHz = 7.5 x 108 x 106 Hz
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A: Given data as per question Surface area of radiator = 15 m2 Temperature =1200 K
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A: Since you have asked multiple question, we will solve the first question for you. If you want any…
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- Electrons are ejected from a metallic surface with speeds ranging up to 4.1 × 105 m/s when light with a wavelength of 630nm is used. What is the cutoff frequency for this surface? Express your answer in terms of 1014 Hz and round it to the nearest hundredth. For example, if you get 1.234 x 1014 Hz, you type in 1.23. (Hint: you should first calculate the work function of the surface.) Use h=6.626x1034 Js; c=3 x108 m/s. ; me=9.11x10-31kg Js; c=3 x108 m/s. ; me=9.11x1031kgfind the temperature of the coolest star whose peak blackbody wavelength can be observed with the human eye (the exact range of visible light varies from publication to publication, so use 380nm to 750 nm).Show that, if the ratio of the blackbody fluxes from a star at two different frequencies (i.e., a color) is measured, then, in principle, the surface temperature of the star can be derived, even if the star's solid angle on the sky is unknown (e.g., if it is too distant to be resolved, and its distance and surface area are both unknown).
- Calculate the wavelength (λ) for an ultraviolet photon having a frequency ν = 2.33 × 1015 s–1. Express your answer in units of nanometers.1.2) In a region of gas where the optical depth is 2.0, what percentage of photons can escape without being scattered or absorbed?A blackbody is brightest at a wavelength of 800 nm. At what wavelength would the blackbody be brightest if its temperature were tripled?
- A material has a mass attenuation coefficient of 0.35 cm²/g (for a given photon energy) and has a density of 1 g/cm³. What is the thickness of the Half-Value Layer (HVL) of this material? (Note: the Half-Value Layer is the material thickness required to reduce an incident beam intensity by a factor of two).Calculate the energy of a photon of frequency 3.5 x 1015 Hz, in electronvolts (eV). Do an online search to find the conversion factor between electronvolts and joules.