What is the total amount of heat absorbed in kJ when 39 grams of diethyl ether at 20 °C is heated to 136 °C? Molar Mass: 74g/mol Melting Point: -116°C Boiling Point: 34.5 °C Heat of Fusion (Hvap) 7,270 J/mol Heat of Vaporization (Hvap) 27,710 J/mol Cs(1) = 3.74 J/g-°C cs(g) = 2.35 J/g.°C Show work on upload.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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What is the total amount of heat absorbed in kJ when 39 grams of
diethyl ether at 20 °C is heated to 136 °C?
Molar Mass: 74g/mol
Melting Point: -116°C
Boiling Point: 34.5 °C
Heat of Fusion (Hvap) 7,270 J/mol
Heat of Vaporization (Hvap) 27,710 J/mol
Cs(1) = 3.74 J/g.°C cs(g) = 2.35 J/g•°C
Show work on upload.
Transcribed Image Text:What is the total amount of heat absorbed in kJ when 39 grams of diethyl ether at 20 °C is heated to 136 °C? Molar Mass: 74g/mol Melting Point: -116°C Boiling Point: 34.5 °C Heat of Fusion (Hvap) 7,270 J/mol Heat of Vaporization (Hvap) 27,710 J/mol Cs(1) = 3.74 J/g.°C cs(g) = 2.35 J/g•°C Show work on upload.
Expert Solution
Step 1

Since the initial temperature of specie is more than the melting point point temperature and less than the boiling point temperature.

Hence the specie will be in liquid phase initially.

And since the final temperature of specie is more than the boiling point temperature. Hence the final phase of the specie will be gas.

In the above heating process, following steps will take place.

1) Heating of liquid from 20 oC to its boiling point temperature i.e 34.5 oC.

2) Evaporating liquid into gas at boiling point temperature i.e 34.5 oC

3) Heating of gas from boiling point temperature i.e 34.5 oC to final temperature i.e 136 oC.

 

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