SAE 5.16 From the following enthalpies of reaction 2 H₂(g) + O₂(g) H₂(g) + O₂(g) → calculate AH for the reaction 2 H₂O₂(1) 2H₂O(1) AH = -572 kJ H₂O₂ (1) AH = -188 kJ 2 H₂O(1) + O₂(g).

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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how would I use hess's law? use steps please 

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b. i and ii are true.
SAE 5.16 From the following enthalpies of reaction
calculate AH for the reaction
a. -196 kJ
b. -384 kJ
c. -760 kJ
d. -948 kJ
17
FEB
12
O
Chapter 5: Thermochemistry
2 H₂(g) + O₂(8) → 2H2O(I)
H₂(g) + O₂(g) →→→ H₂O₂ (1)
tv
2 H₂O₂ (1) 2 H₂O(l) + O₂(g).
·
184
-
X
>
ΔΗ = -572 kJ
AH = -188 kJ
P Pearson eText
NIZA
2
W
X
P 5.6: Hess's Law
P
= 0
Mon Feb 12 5:44 PM
X +
Relaunch to update :
X
All Bookmarks
AB
Transcribed Image Text:Chrome File Edit View History Bookmarks Profiles Tab Window Help ← → C G !!!! Q m A₁ O Chapter 3 Quiz Uplcx | 0 Chapter 3 Before R X OD 5 (20) Thermochemic x WH 3 Ways to Calculate Course Home plus.pearson.com/courses/stoltzfus44973/products/BRNT-33RZ6AFHI19/pages/20887fc0-78ab-11ec-ab70-b9bc2e7b92ec?key=621797821711266... b. i and ii are true. SAE 5.16 From the following enthalpies of reaction calculate AH for the reaction a. -196 kJ b. -384 kJ c. -760 kJ d. -948 kJ 17 FEB 12 O Chapter 5: Thermochemistry 2 H₂(g) + O₂(8) → 2H2O(I) H₂(g) + O₂(g) →→→ H₂O₂ (1) tv 2 H₂O₂ (1) 2 H₂O(l) + O₂(g). · 184 - X > ΔΗ = -572 kJ AH = -188 kJ P Pearson eText NIZA 2 W X P 5.6: Hess's Law P = 0 Mon Feb 12 5:44 PM X + Relaunch to update : X All Bookmarks AB
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