What is the terminating condition in the following code? int factorial(int n) { if(n <= 1) return 1; else return(n * factorial(n-1)); }
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A: Given :
What is the terminating condition in the following code?
int factorial(int n)
{
if(n <= 1)
return 1;
else
return(n * factorial(n-1));
}
Step by step
Solved in 2 steps
- Can you fix this please? with 5 53 5099 1223 567 17 4 1871 8069 3581 6841 #include <iostream>using namespace std; const int SORT_MAX_SIZE = 8; bool IsPrimeRecur(int dividend, int divisor) { if (divisor == 1) { return true; } if (dividend % divisor == 0) { return false; } return IsPrimeRecur(dividend, divisor-1);} bool IsArrayPrimeRecur(int arr[], int size, int index) { cout << "Entering IsArrayPrimeRecur" << endl; if (index == size) { cout << "Leaving IsArrayPrimeRecur" << endl; return true; } if (!IsPrimeRecur(arr[index], arr[index]-1)) { cout << "Leaving IsArrayPrimeRecur" << endl; return false; } return IsArrayPrimeRecur(arr, size, index+1);} bool IsArrayPrimeIter(int arr[], int size) { cout << "Entering IsArrayPrimeIter" << endl; for (int i = 0; i < size; i++) { for (int j = 2; j < arr[i]; j++) { if (arr[i] % j == 0) {…#include using namespace std; int main() { int stop; int result; int n; } cin >> stop; result = 0; Type the program's output for (n = 0; n stop) { cout << "n=" << n; cout << endl; break; } } cout << result << endl; return 0; Input 7 OutputCarefully consider the code segment below and answer the following questions : int result =0; for(int i =0 ; i=0 [ result ++; count - - ; ] ] (1) What will the value of the result variable be after the code has executed? ]
- i need help debuging this #include <stdio.h> int printBin(int value); int main(){ int num=10;int tobinary= printBin(num);printf("The number %d converted to binary as %d",num,tobinary);} unsigned int x = 1; char *ccc = (char*)&x; if (*ccc){ printf("This is Little endian"); } else{ printf("This is Big endian"); } getchar(); return 0; } int printBin(int value){ if(value<2)return value; return printBin(value / 2) *10 + value % 2; }Assume that M is declared as int, and a value is stored in it. How would you check * ? whether N is between 3 and 9 if (M 9) // N is in valid range if (M > 3 && M 9) // N is in valid range if (M >= 3 || M = 3 &&N 100) cout100) cout>>'too many"; O if (count<100) cout<<"too many"; What will be displayed by the following segment of code? int option = 7: switch(option) (case 1: cout << "Purdue" << endl;break; case 2: cout << "Michigan" Ss endl:break: case 3: cout << "IU" << endl;break; default: cout << "IUPUI"Note: It`s C++in the C++ version please suppose to have a score corresponding with probabilities at the end and do not use the count[] function. Please explain the detail when coding. DO NOT USE ARRAY. The game of Pig The game of Pig is a dice game with simple rules: Two players race to reach 100 points. Each turn, a player repeatedly rolls a die until either a 1 ("pig") is rolled or the player holds and scores the sum of the rolls (i.e. the turn total). At any time during a player's turn, the player is faced with two decisions: roll - if the player rolls 1: the player scores nothing and it becomes the opponents turn. 2 - 6: the number is added to the player's turn total and the player's turn continues. hold - The turn total is added to the player's score and it becomes the opponent's turn. This game is a game of probability. Players can use their knowledge of probabilities to make an educated game decision. Assignment specifications Hold-at-20 means that the player will choose to roll…Q2: What is the output for the following codes: 1- int arr[4]= {2, 6, 7, 8}; for (int i= 3; i>=0; i--) cout<i need help debuging this #include <stdio.h> int printBin(int value); int main(){ int num=10;int tobinary= printBin(num);printf("The number %d converted to binary as %d",num,tobinary);} unsigned int x = 1; char *ccc = (char*)&x; if (*ccc){ printf("This is Little endian"); } else{ printf("This is Big endian"); } getchar(); return 0; } int printBin(int value){ if(value<2)return value; return printBin(value / 2) *10 + value % 2; }Using the following description, please replace the return line in C code; /* * logicalShift: logical shift x to the right by n, * where 0 <= n <= 31 * Examples: * logicalShift(0xFFFFFFFF,0) = 0xFFFFFFFF * logicalShift(0xFFFFFFFF,1) = 0x7FFFFFFF * logicalShift(0xFFFFFFFF,2) = 0x3FFFFFFF * logicalShift(0xFFFFFFFF,3) = 0x1FFFFFFF * logicalShift(0xFFFFFFFF,4) = 0x0FFFFFFF * logicalShift(0xFFFFFFFF,8) = 0x00FFFFFF * logicalShift(0xFFFFFFFF,12) = 0x000FFFFF * Legal ops: ! ~ & ^ | + << >> * Max ops: 20 * Rating: 3 * Hints/notes: * */ int logicalShift(int x, int n) { return 2 } You cannot: 1. Use any control constructs such as if, do, while, for, switch, etc. 2. Define or use any macros. 3. Define any additional functions in this file. 4. Call any functions. 5. Use any other operations, such as &&, ||, -, or ?:, not listed in the the "Legal ops" list for the function. 6. Use any form of casting. 7. Use any data type other than int.▾ Problem 1 Write a generator for the Fibonacci Numbers Build a generator that returns the Ebonacci numbers: 0, 1, 1, 2, 3, 5, and so on. [] def fibonacci_generator(): ***Generates all Fibonacci numbers.*** YOUR CODE HERE File "cipython-input-11-7871f3cb2839>", line 5 if n 100: bresk assert r == [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144] [] Hidden tests, 5 points * These tests check basically that you generate Fibonacci nunters, forever without stopping. It is the reader (the user) of the function that decides when to stop.Fix this code #include <stdio.h> int main(void){printf("unknown person\n");printf("Greates number --->\n");printf("smallest number --->\n");printf("************************\n");printf("Enter Your Choice :"); char ch; scanf("%c", &ch); if (ch == "G");int number1;int number2; printf("Enter two integer numbers :");scanf("%d \n %d", &number1, &number2); if(number1>number2) printf("%d is the greatest number\n", &number1); else printf("%d is the greatest number\n", &number2); } else if (ch == "S");int number1;int number2; { printf("Enter two integer numbers :"); scanf("%d \n %d", &number1, &number2); if (number1<number2) printf("%d is the greatest number\n", &number1); else printf("%d is the greatest number\n", &number2); return 0;}SEE MORE QUESTIONSRecommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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