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What is the solution of given initial value problem? =y+sin t df2 da + cost dt de * (0) = 1, a' (0) = 0, y(0) = -1, 3 (0) = -1 O a. * (t) = sin t, y(t) = - cost – sin t O b. (t) = sin t, y(t) = cost +sin t O c a (t) = cost, y(t) = - cost – sin t O d. # (t) = cost, y(t) = cost – sin t e. (t) = cost, y(t) = - cost + sint

What is the solution of given initial value problem? =y+sin t df2 da + cost dt de * (0) = 1, a' (0) = 0, y(0) = -1, 3 (0) = -1 O a. * (t) = sin t, y(t) = - cost – sin t O b. (t) = sin t, y(t) = cost +sin t O c a (t) = cost, y(t) = - cost – sin t O d. # (t) = cost, y(t) = cost – sin t e. (t) = cost, y(t) = - cost + sint

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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What is the solution of given initial value problem? = y +sin t dt2 da + cost dt * (0) = 1, a (0) = 0, y(0) = - 1, y (0) = -1 O a. * (t) = sin t, y(t) = - cost – sin t O b. (t) = sin t, y(t) = cost sin t C. * (t) = cost, y(t) = - cost – sin t O d. a (t) = cost, y(t) = cost – sin t O e. (t) = cost, y(t) = – cost + sin t
Transcribed Image Text:What is the solution of given initial value problem? = y +sin t dt2 da + cost dt * (0) = 1, a (0) = 0, y(0) = - 1, y (0) = -1 O a. * (t) = sin t, y(t) = - cost – sin t O b. (t) = sin t, y(t) = cost sin t C. * (t) = cost, y(t) = - cost – sin t O d. a (t) = cost, y(t) = cost – sin t O e. (t) = cost, y(t) = – cost + sin t
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