y'+2y/x=x, y(1)=2, y(2) using h=0.1

Q: (1-x) y'= y?

A: We have to solve the given differential equation

Q: Find y' y= (x2+2)(x-3)

A: Given :                  y = x2+2x-3 Find :               y'

Q: h(t) = 4e5t-7t-3 Determine the value of h'(-1).

A: Given query is to find indicated derivative.

Q: Find y as a function of a if y(1) = 3, y'(1) = -7. y = r²y" + 3xy' - 63y = 0,

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Q: for

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Q: Find y'  if e x/y      = x   -y

A:

Q: Differentiate the function. y = V7 + 4e3x y' = %3D

A: The function is  y=7+4e3x

Q: Find y' if xy =yx

A: Given: xy=yx for finding y', we first take log both side then simplify it and in last find…

Q: 7 (2+ x³)' Vx² – 1 (x2 + x + 1)* 3 d B : dx - 4

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Q: (пх)2 find y'

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Q: Find y' for y = 7x-3+ 5x - 1

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Q: Find y' and y "   y =x2In(2x).

A: Given: y= x2ln2xDifferentiation Formula:ddxlnx=1xddxxn=nxn-1ddxuv=uv'+vu'

Q: Find y' if y= is-2x(+)* +

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Q: y = 2" In (cot (Tx))

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Q: Find y' for x^4y^3−3x+2y=24 at the point (−2,1).

A: We have, x4y3−3x+2y=24 Using the chain rule of differentiation,…

Q: Find y' for y= [1 + *(¹ + ³) ³. 3 3 X y' =

A: We need to find second derivative.

Q: y' = x^3 - 2xy when x=1, y=1

A: Given differential equation:   y'=x3-2xy   when x=1; y=1   y'+2xy=x3:  is a linear differential…

Q: Evaluate dy/dx @ the given point y^5-4=x^5-2y  @ (-1,1)

A: The given equation is  y5 - 4 = x5 - 2y We know that (d/dx) xn = nxn-1

Q: Find y' for y = 2x - 8x - 6 - 1 y' = %3D

A: As we have to find y', that is derivative of function y with respect to 'x' , just I have used the…

Q: (3– 3cos5x)} (3x² +2x-7)² (e - sinx +3x) y= Find dy/dx if

A: That's computational, take a careful look.

Q: Find y'(2)  y=ex2−ay=ex2−a where a=4

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Q: Find y' if exy = e 4x -esy-

A: NOTE: Refresh your page if you can't see any equations. .

Q: Evaluate y' if y = vtan x

A: We solve the problem by doing the derivative using the formula.

Q: Find y as a function of a if y(0) = 1, y/(0)=-18, /'(0) = 27. y(z) = y" +9y = 0,

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Q: dy x²-3xy² Given = dx 3x²y-6y²-1 determine the function f. and f = f(3xy² - x²) + g(y); y = constant

A: Mdx + Ndy = 0 ----?(1)is exact,

Q: given that  x^2y^2+3x=y^3-1 use implicit differeniation to find the value of y'(1,2) a.3/2…

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Q: Find y' at the specified point. x² + y? = 81, at (0, – 9) y'

A: Given, The curve x2+y2=81 We have to find y' at the point 0, -9.