What is the solubility of Cr(OH), at a pH of 10.70? (Ksp Cr(OH)₂ is 6.70 × 10-31)

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Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Question:**

What is the solubility of Cr(OH)₃ at a pH of 10.70? (Ksp Cr(OH)₃ is 6.70 × 10⁻³¹)

**Explanation:**

This question involves finding the solubility of chromium(III) hydroxide, Cr(OH)₃, in a solution with a pH of 10.70, given its solubility product constant (Ksp) as 6.70 × 10⁻³¹.

**Approach:**

To solve this, we need to use the solubility product expression for Cr(OH)₃:

\[ \text{Cr(OH)}₃(s) \leftrightarrow \text{Cr}^{3+}(aq) + 3\text{OH}^{-}(aq) \]

The Ksp expression is:

\[ Ksp = [\text{Cr}^{3+}][\text{OH}^-]^3 \]

Knowing the pH allows us to find the concentration of OH⁻ ions since:

\[ \text{pH} + \text{pOH} = 14 \]

\[ \text{pOH} = 14 - 10.70 = 3.30 \]

\[ [\text{OH}^-] = 10^{-\text{pOH}} = 10^{-3.30} \]

Plugging this [OH⁻] value into the Ksp expression will allow us to solve for [Cr³⁺] and thus determine the solubility.
Transcribed Image Text:**Question:** What is the solubility of Cr(OH)₃ at a pH of 10.70? (Ksp Cr(OH)₃ is 6.70 × 10⁻³¹) **Explanation:** This question involves finding the solubility of chromium(III) hydroxide, Cr(OH)₃, in a solution with a pH of 10.70, given its solubility product constant (Ksp) as 6.70 × 10⁻³¹. **Approach:** To solve this, we need to use the solubility product expression for Cr(OH)₃: \[ \text{Cr(OH)}₃(s) \leftrightarrow \text{Cr}^{3+}(aq) + 3\text{OH}^{-}(aq) \] The Ksp expression is: \[ Ksp = [\text{Cr}^{3+}][\text{OH}^-]^3 \] Knowing the pH allows us to find the concentration of OH⁻ ions since: \[ \text{pH} + \text{pOH} = 14 \] \[ \text{pOH} = 14 - 10.70 = 3.30 \] \[ [\text{OH}^-] = 10^{-\text{pOH}} = 10^{-3.30} \] Plugging this [OH⁻] value into the Ksp expression will allow us to solve for [Cr³⁺] and thus determine the solubility.
Expert Solution
Step 1: List the Given Data

The pH of Cr(OH)3 is 10.70.

The Ksp value is 6.70 cross times 10 to the power of negative 31 end exponent.

To find the solubility of Cr(OH)3.

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