You look at the solubility of Ca(OH)2 in water (Ksp = 4 x 10^–10). You wait until the system reaches equilibrium and then add Cr(C2H3O2)3. (Ksp = 6.7 x 10^–31 for Cr(OH)3). What happens to the solubility of Ca(OH)2? Explain why? A) Less soluble (more Ca(OH)2 precipitate) B) More soluble (more Ca2+ cations and OH– dissolve from calcium hydroxide solid) C) Nothing happens. system remains at equlibrium

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